每天刷个算法题20160521:二叉树高度(递归与非递归)
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http://blog.csdn.net/xiaofei_it/article/details/51502727
为了防止思维僵化,每天刷个算法题。已经刷了几天了,现在发点代码。
我已经建了一个开源项目,每天的题目都在里面:
https://github.com/Xiaofei-it/Algorithms
绝大部分算法都是我自己写的,没有参考网上通用代码。读者可能会觉得有的代码晦涩难懂,因为那是我自己的理解。
最近几天都是在写一些原来的东西,大多数是非递归。以后准备刷点DP、贪心之类的题。
下面是二叉树高度(递归与非递归):
/**
*
* Copyright 2016 Xiaofei
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*
*/
package xiaofei.algorithm;
import java.util.Stack;
/**
* Created by Xiaofei on 16/5/21.
*
* I am writing code in Starbucks alone.
*
* What a sad picture!!!
*
* I cannot remember when I drank coffee with somebody else last time.
*
*/
public class BinaryTreeHeight
public static int calculateRecursively(BinaryTreeNode root)
if (root == null)
return 0;
else
return Math.max(calculateRecursively(root.left), calculateRecursively(root.right)) + 1;
public static int calculateCorecursively(BinaryTreeNode root)
//当年ACM的时候总喜欢自己写queue或者stack,几乎不用C++的STL库。现在想用一下Java的Stack
class Element
BinaryTreeNode node;
int left;
int right;
Element(BinaryTreeNode node)
this.node = node;
left = right = -1;
Stack<Element> stack = new Stack<>();
stack.push(new Element(root));
int result = -1;
while (!stack.empty())
Element element = stack.peek();
if (element.node == null)
stack.pop();
if (stack.isEmpty())
result = 0;
else
Element tmp = stack.peek();
if (tmp.left == -1)
tmp.left = 0;
else
tmp.right = 0;
else if (element.left == -1)
stack.push(new Element(element.node.left));
else if (element.right == -1)
stack.push(new Element(element.node.right));
else
Element tmp1 = stack.pop();
int height = Math.max(tmp1.left, tmp1.right) + 1;
if (stack.isEmpty())
result = height;
else
Element tmp2 = stack.peek();
if (tmp2.left == -1)
tmp2.left = height;
else
tmp2.right = height;
return result;
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