gson与fastjson

Posted 2022-08-03 盖丽男

背景

公司里对安全比较看重，然后最近fastjson漏洞出现的频繁了一点，所以要求，尽量不要使用fastjson，因此组长选了gson作为代替品。

使用

关于json，我在代码里，最常用的有两个地方，一个是做类型转换的时候用，另一个是偷懒，在调用第三方接口的时候接数据用。下面分别看一下gson和fastjson的使用

gson

        /**
         * List《==》json
         */
        List<String> stringList = Lists.newArrayList("a", "b", "c", "d");
        String listJsonString = gson.toJson(stringList);
        System.out.println(stringList);
        System.out.println(listJsonString);
        List<String> jsonString = gson.fromJson(listJsonString, new TypeToken<List<String>>().getType());
        System.out.println(jsonString);

        /**
         * map <==> json
         */
        Map<Integer, String> stringMap = new HashMap<>();
        stringMap.put(1, "one");
        stringMap.put(2, "two");
        String mapJson = gson.toJson(stringMap);
        Map<Integer, String> jsonD = gson.fromJson(mapJson, new TypeToken<Map<Integer, String>>().getType());
        System.out.println(jsonD);
        System.out.println(jsonD.get(1));


        /**
         * List<object> <==> json
         */
        Customer customer = customerMapper.selectByPrimaryKey(1);

        List<Customer> customers = new ArrayList<>();
        customers.add(customer);
        customers.add(customer);
        String customerListString = gson.toJson(customers);
        System.out.println(customerListString);
        List<Customer> deS = gson.fromJson(customerListString, List.class);
        System.out.println(deS);

        /**
         * object <==> json
         */
        String customerJson = gson.toJson(customer);
        JsonObject jsonObject = gson.fromJson(customerJson, JsonObject.class);
        String crmId = jsonObject.get("crmId").getAsString();
        System.out.println("crmId:" + crmId);

        Customer customer1 = gson.fromJson(customerJson, Customer.class);
        System.out.println(customer1);

fastjson

        /**
         * List《==》fastjson
         */
        List<String> stringList = Lists.newArrayList("a", "b", "c", "d");
        String listJsonString = JSONObject.toJSONString(stringList);
        System.out.println(stringList);
        System.out.println(listJsonString);
        List<String> jsonString = JSONObject.parseArray(listJsonString, String.class);
        System.out.println(jsonString);

        /**
         * map <==> json
         */
        Map<Integer, String> stringMap = new HashMap<>();
        stringMap.put(1, "one");
        stringMap.put(2, "two");
        String mapJson = JSONObject.toJSONString(stringMap);
        Map<Integer, String> jsonD = (Map<Integer, String>) JSONObject.parse(mapJson);
        System.out.println(jsonD);
        System.out.println(jsonD.get(1));


        /**
         * List<object> <==> json
         */
        Customer customer = customerMapper.selectByPrimaryKey(1);

        List<Customer> customers = new ArrayList<>();
        customers.add(customer);
        customers.add(customer);
        String customerListString = JSONObject.toJSONString(customers);
        System.out.println(customerListString);
        List<Customer> deS = JSONObject.parseArray(customerListString, Customer.class);
        System.out.println(deS);


        /**
         * object <==> json
         */
        String customerJson = JSONObject.toJSONString(customer);
        JSONObject jsonObject = JSONObject.parseObject(customerJson);
        String crmId = jsonObject.getString("crmId");
        System.out.println("crmId:" + crmId);

        Customer customer1 = JSONObject.parseObject(customerJson, Customer.class);
        System.out.println(customer1);

选择

从速度上来说，fastjson是比gson快的，我们的服务目前来说，还没有到考虑性能的时候，所以目前从fastjson切换到gson，先暂时不解决性能问题。