Python递归提取嵌套列表的所有元素

Posted 2022-07-15 Channing Lewis

alist = [1, 2, ['a', ['b2'], ['cc', 5, 8, [10]]]]

def all_ele(lis):
    result_list = []
    for i in lis:
        if type(i) == list:
            result_list += all_ele(i)
        else:
            result_list.append(i)
    return result_list

print(all_ele(alist))

输出：

[1, 2, 'a', 'b2', 'cc', 5, 8, 10]