[LeetCode] Merge Two Binary Trees
Posted immjc
tags:
篇首语：本文由小常识网(cha138.com)小编为大家整理，主要介绍了[LeetCode] Merge Two Binary Trees相关的知识，希望对你有一定的参考价值。
Given two binary trees and imagine that when you put one of them to cover the other, some nodes of the two trees are overlapped while the others are not.
You need to merge them into a new binary tree. The merge rule is that if two nodes overlap, then sum node values up as the new value of the merged node. Otherwise, the NOT null node will be used as the node of new tree.
Example 1:
Input:
Tree 1 Tree 2
1 2
/ \ / \
3 2 1 3
/ \ \
5 4 7
Output:
Merged tree:
3
/ 4 5
/ \ \
5 4 7
Note: The merging process must start from the root nodes of both trees.
根据题意使用递归生成一棵新的二叉树。类似的，也可以在t1或者t2的基础上对树进行拓展。
class Solution { public: TreeNode* mergeTrees(TreeNode* t1, TreeNode* t2) { if (t1 == nullptr) return t2; if (t2 == nullptr) return t1; TreeNode* root = new TreeNode(t1->val + t2->val); root->left = mergeTrees(t1->left, t2->left); root->right = mergeTrees(t1->right, t2->right); return root; } }; // 43 ms
以上是关于[LeetCode] Merge Two Binary Trees的主要内容，如果未能解决你的问题，请参考以下文章
[leetcode]Merge Two Sorted Lists
LeetCode - 21. Merge Two Sorted Lists
Leetcode---21. Merge Two Sorted Lists
[LeetCode] Merge Two Binary Trees