跑步锻炼（蓝桥杯）

Posted 2022-01-22 Koi279

这道题我一天写了两次，第一次只想快点写出来，一个字，干，

结果用switch写出来一个大块头

代码如下

#include<stdio.h>
int run(int i)

	if((i%400==0||(i%4==0&&i%100!=0))) return 1;
	else return 0;

int main()

	int weeknum=0,monthnum=0,i,j,day=0,weekmonth=0;
	for(i=2000;i<2020;i++)
	for(j=1;j<=12;j++)
	
		switch(j)
		
			case 1:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 2:if((day-2)%7==0) weekmonth+=1;if(run(i)) day+=29; else day+=28;monthnum+=1;break;
			case 3:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 4:if((day-2)%7==0) weekmonth+=1;day+=30;monthnum+=1;break;
			case 5:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 6:if((day-2)%7==0) weekmonth+=1;day+=30;monthnum+=1;break;
			case 7:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 8:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 9:if((day-2)%7==0) weekmonth+=1;day+=30;monthnum+=1;break;
			case 10:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 11:if((day-2)%7==0) weekmonth+=1;day+=30;monthnum+=1;break;
			case 12:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
		
	
	for(j=1;j<10;j++)
	
		switch(j)
		
			case 1:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 2:if((day-2)%7==0) weekmonth+=1;if(run(i)) day+=29; else day+=28;monthnum+=1;break;
			case 3:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 4:if((day-2)%7==0) weekmonth+=1;day+=30;monthnum+=1;break;
			case 5:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 6:if((day-2)%7==0) weekmonth+=1;day+=30;monthnum+=1;break;
			case 7:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 8:if((day-2)%7==0) weekmonth+=1;day+=31;monthnum+=1;break;
			case 9:if((day-2)%7==0) weekmonth+=1;day+=30;monthnum+=1;break;
		
	
	day+=1;monthnum+=1;
	weeknum=(day-3)/7+1;
	int all=day+weeknum+monthnum-weekmonth;	
	printf("%d",all);
	return 0;

 代码的啰嗦程度不敢恭维，

还好结果对了

没办法，程序太丑，自己都嫌弃，所以我马上又写了一次，

这次先理了理思路再写的，看着就简洁多了。

第二次的代码如下

#include<stdio.h>
int run(int i)

	if((i%400==0||(i%4==0&&i%100!=0))) return 1;
	else return 0;

int main()

	int month[13]=0,31,0,31,30,31,30,31,31,30,31,30,31;
	int i,j,day=0,monthnum=0,weeknum=0,weekmonth=0;
	for(i=2000;i<=2020;i++)
	
		if(run(i)) month[2]=29;
		else month[2]=28;
		for(j=1;j<=12;j++)
		
			if(i==2020&&j==10) break;
			if((day-2)%7==0) weekmonth+=1;
			monthnum+=1; day+=month[j];
		
	
	weeknum=(day-3)/7+1;
	int all=day+1+weeknum+monthnum+1-weekmonth;	
	printf("%d",all);
	return 0;
  

代码直接少了一半多，不错不错。

答案也没问题 

改 ~~真理啊！