JavaScript计算日期差时间差倒计时距离未来节日倒计时放假倒计时

Posted 2022-01-08 web半晨

目录

• 1、实现代码
• 2、调用
• 3、效果演示

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1、实现代码

function distanceFromTheFuture(key = 1, futureDate = '2027-01-01 00:00:00') 
	futureDate = new Date(futureDate);
	let nowDate = new Date(),
		distanceFestival = futureDate - nowDate,
		day = parseInt(distanceFestival / (1000 * 60 * 60 * 24)),
		hour = parseInt(distanceFestival % (1000 * 60 * 60 * 24) / (1000 * 60 * 60)),
		minutes = parseInt(distanceFestival % (1000 * 60 * 60) / (1000 * 60)),
		seconds = parseInt(distanceFestival % (1000 * 60 * 60) % (1000 * 60) / 1000),
		result = null;

	switch (key) 
		case 1:
			result = `$day天$hour时$minutes分$seconds秒`;
			break;
		case 2:
			result = `$day`;
			break;
		case 3:
			result = `$hour`;
			break;
		case 4:
			result = `$minutes`;
			break;
		case 5:
			result = `$seconds`;
			break;
		default:
			console.log("出错啦！");
			break;
	
	return result;

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2、调用

// 参数说明
// 第一个参数 key 表示要返回的值
// 第二个参数 futureDate 表示未来的时间
console.log(distanceFromTheFuture('2', '2022-01-01 00:00:00'));

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3、效果演示

小程序码

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