C语言实现扫雷小游戏
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首先来规划一下扫雷游戏实现的几个步骤:
初始化棋盘:二维数组的遍历及赋值
为了后续代码的简洁方便,我们用’0’来初始化
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
int i = 0;
int j = 0;
for (i = 0; i < rows; i++)
for (j = 0; j < cols; j++)
board[i][j] = set;
布置雷的信息:应用随机函数进行赋值
void SetMine(char mine[ROWS][COLS], int row, int col)
int count = EASY_COUNT;
while (count)
int x = rand() % row + 1;
int y = rand() % col + 1;
if (mine[x][y] == '0')
mine[x][y] = '1';
count--;
排查雷:
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
int x = 0;
int y = 0;
int win = 0;
while (win<row*col- EASY_COUNT)
printf("请输入要排查的坐标->");
scanf("%d %d", &x, &y);
if (x >= 1 && x <= row && y >= 1 && y <= col)
if (mine[x][y] == '1')
printf("很遗憾你被炸死了\\n");
DisplayBoard(mine, row, col);
break;
else
//计算x,y坐标周围有几个雷
int n=get_mine_count(mine, x, y);
show[x][y] = n + '0';
DisplayBoard(show, row, col);
win++;
else
printf("输入坐标错误,请重新输入\\n");
if (win == row * col - EASY_COUNT)
printf("恭喜你,排雷成功\\n");
DisplayBoard(mine, row, col);
下面是游戏实现的完整代码,依旧是分为了3个版块,为了更好的管理代码,提高代码的可读性和可移植性
game2.h
#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#define ROW 9
#define COL 9
#define EASY_COUNT 10
#define ROWS ROW+2
#define COLS COL+2
//初始化棋盘
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
//打印棋盘
void DisplayBoard(char board[ROWS][COLS], int row, int col);
//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col);
//排查雷
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);
game2.c
#include "game2.h"
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
int i = 0;
int j = 0;
for (i = 0; i < rows; i++)
for (j = 0; j < cols; j++)
board[i][j] = set;
void DisplayBoard(char board[ROWS][COLS], int row, int col)
int i = 0;
int j = 0;
for (i = 0; i <= col; i++)
printf("%d ", i);
printf("\\n");
for (i = 1; i <= row; i++)
printf("%d ", i);
for (j = 1; j <= col; j++)
printf("%c ", board[i][j]);
printf("\\n");
//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col)
int count = EASY_COUNT;
while (count)
int x = rand() % row + 1;
int y = rand() % col + 1;
if (mine[x][y] == '0')
mine[x][y] = '1';
count--;
static int get_mine_count(char mine[ROWS][COLS], int x, int y)
return mine[x - 1][y] +
mine[x - 1][y - 1] +
mine[x][y - 1] +
mine[x + 1][y] +
mine[x + 1][y + 1] +
mine[x][y + 1] +
mine[x - 1][y + 1]+
mine[x+1][y-1]-8*'0';
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
int x = 0;
int y = 0;
int win = 0;
while (win<row*col- EASY_COUNT)
printf("请输入要排查的坐标->");
scanf("%d %d", &x, &y);
if (x >= 1 && x <= row && y >= 1 && y <= col)
if (mine[x][y] == '1')
printf("很遗憾你被炸死了\\n");
DisplayBoard(mine, row, col);
break;
else
//计算x,y坐标周围有几个雷
int n=get_mine_count(mine, x, y);
show[x][y] = n + '0';
DisplayBoard(show, row, col);
win++;
else
printf("输入坐标错误,请重新输入\\n");
if (win == row * col - EASY_COUNT)
printf("恭喜你,排雷成功\\n");
DisplayBoard(mine, row, col);
test.c
#include "game2.h"
void menu()
printf("**************************\\n");
printf("******* 1.play *******\\n");
printf("******* 0.exit *******\\n");
printf("**************************\\n");
void game()
//创建数组
char mine[ROWS][COLS] = 0 ;//存放布置好的雷的信息
char show[ROWS][COLS] = 0 ;//存放排查出的雷的信息
//初始化mine数组全部为‘0’
InitBoard(mine, ROWS, COLS, '0');
//初始化show数组全部为‘0’
InitBoard(show, ROWS, COLS, '*');
//打印棋盘
//DisplayBoard(mine, ROW, COL);
//布置雷
SetMine(mine, ROW, COL);
DisplayBoard(show, ROW, COL);
//DisplayBoard(mine, ROW, COL);
//排查雷
FindMine(mine, show, ROW, COL);
void test()
int input = 0;
srand((unsigned int)time(NULL));
do
menu();
printf("请选择->");
scanf("%d", &input);
switch (input)
case 1:
game();
break;
case 0:
printf("退出游戏\\n");
break;
default:
printf("选择错误\\n");
break;
while (input);
int main()
test();
return 0;
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C语言实现小游戏篇我接触的第一款电脑游戏,你可以永远相信 “ 扫雷 ” 。[ C语言实现 ] [ 超详细,超清楚 ] [ 有代码 ]