1088 Rational Arithmetic (20 分)难度: 简单 / 知识点: 模拟
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https://pintia.cn/problem-sets/994805342720868352/problems/994805378443755520
PAT乙级的原题,直接模拟即可
#include<bits/stdc++.h>
using namespace std;
typedef long long int LL;
LL a,b,c,d;
LL gcd(LL a,LL b) {return b?gcd(b,a%b):a;}
void print(LL a,LL b)
{
LL temp=gcd(abs(a),abs(b));
int flag=1;//记录数的正负
if(a<0) flag=flag*(-1),a=abs(a);
if(b<0) flag=flag*(-1),b=abs(b);
a/=temp,b/=temp;
LL cnt=a/b;
a=a-cnt*b;
if(cnt==0&&a==0) flag=1;
if(flag<0) cout<<"(";
if(a==0) printf("%lld",cnt*flag);
else if(cnt&&a) printf("%lld %lld/%lld",cnt*flag,a,b);
else if(!cnt&&a) printf("%lld/%lld",a*flag,b);
if(flag<0) cout<<")";
}
int main(void)
{
scanf("%lld/%lld %lld/%lld",&a,&b,&c,&d);
print(a,b),printf(" + "),print(c,d),printf(" = "),print(a*d+c*b,b*d);
puts("");
print(a,b),printf(" - "),print(c,d),printf(" = "),print(a*d-c*b,b*d);
puts("");
print(a,b),printf(" * "),print(c,d),printf(" = "),print(a*c,b*d);
puts("");
print(a,b),printf(" / "),print(c,d),printf(" = ");
if(b*c!=0) print(a*d,b*c);
else printf("Inf");
return 0;
}
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