[leetcode-508-Most Frequent Subtree Sum]

Posted 2020-09-20 hellowOOOrld

Given the root of a tree, you are asked to find the most frequent subtree sum.
The subtree sum of a node is defined as the sum of all the node values formed by the subtree rooted at
that node (including the node itself). So what is the most frequent subtree sum value? If there is a tie,
return all the values with the highest frequency in any order.
Examples 1
Input:
  5
 / \
2 -3
return [2, -3, 4], since all the values happen only once, return all of them in any order.
Examples 2
Input:
  5
 / \
2 -5
return [2], since 2 happens twice, however -5 only occur once.

思路:

用一个map记录结点的sum与出现的次数。

int sumofTree(TreeNode* root, map<int, int>&counts, int & maxcount)
     {
         if (root == NULL)return 0;
         int sum = root->val;
         sum += sumofTree(root->left, counts, maxcount);
         sum += sumofTree(root->right, counts, maxcount);
         counts[sum]++;
         maxcount = max(maxcount, counts[sum]);
         return sum;
     }
     vector<int> findFrequentTreeSum(TreeNode* root)
     {
         vector<int>ret;
         map<int, int>counts;
         int maxcount = 0;
         sumofTree(root, counts, maxcount);

         for (auto it = counts.begin(); it != counts.end();it++)
         {
             if (it->second == maxcount)ret.push_back(it->first);              
         }
         return ret;
     }

参考：

https://discuss.leetcode.com/topic/77763/short-clean-c-o-n-solution