《LeetCode之每日一题》:178.外观数列
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题目链接: 外观数列
有关题目
给定一个正整数 n ,输出外观数列的第 n 项。
「外观数列」是一个整数序列,从数字 1 开始,序列中的每一项都是对前一项的描述。
你可以将其视作是由递归公式定义的数字字符串序列:
countAndSay(1) = "1"
countAndSay(n) 是对 countAndSay(n-1) 的描述,然后转换成另一个数字字符串。
前五项如下:
1. 1
2. 11
3. 21
4. 1211
5. 111221
第一项是数字 1
描述前一项,这个数是 1 即 “ 一 个 1 ”,记作 "11"
描述前一项,这个数是 11 即 “ 二 个 1 ” ,记作 "21"
描述前一项,这个数是 21 即 “ 一 个 2 + 一 个 1 ” ,记作 "1211"
描述前一项,这个数是 1211 即 “ 一 个 1 + 一 个 2 + 二 个 1 ” ,记作 "111221"
要 描述 一个数字字符串,首先要将字符串分割为 最小 数量的组,每个组都由连续的最多 相同字符 组成。
然后对于每个组,先描述字符的数量,然后描述字符,形成一个描述组。
要将描述转换为数字字符串,先将每组中的字符数量用数字替换,再将所有描述组连接起来。
示例 1:
输入:n = 1
输出:"1"
解释:这是一个基本样例。
示例 2:
输入:n = 4
输出:"1211"
解释:
countAndSay(1) = "1"
countAndSay(2) = 读 "1" = 一 个 1 = "11"
countAndSay(3) = 读 "11" = 二 个 1 = "21"
countAndSay(4) = 读 "21" = 一 个 2 + 一 个 1 = "12" + "11" = "1211"
提示:
1 <= n <= 30
题解
法一:模拟
代码一:
class Solution {
public:
string countAndSay(int n) {
string ans = "1";
while(--n)
{
string temp = "";
int cnt = 1;
for (int i = 0; i < ans.size(); i++)
{
if (i + 1 < ans.size() && ans[i] == ans[i + 1])
cnt++;
else
{
temp += to_string(cnt) + ans[i];
cnt = 1;
}
}
ans = temp;
}
return ans;
}
};
代码二:
参考官方题解
class Solution {
public:
string countAndSay(int n) {
string prev = "1";
for (int i = 2; i <= n; i++)
{
string curr = "";
int pos = 0, start = 0;
while(pos < prev.size())
{
while(pos < prev.size() && prev[pos] == prev[start])
pos++;
curr += to_string(pos - start) + prev[start];
start = pos;
}
prev = curr;
}
return prev;
}
};
代码三:
参考官方题解评论区下shira_yuki
Tips
std::adjacent_find(First, Last, p)
作用
在P的条件下,从[First, Last)范围内寻找首个满足p的元素
std::exchange(obj, new_value)
以 new_value 替换 obj 的值,并返回 obj 的旧值。
class Solution {
public:
string countAndSay(int n) {
string ans = "1", temp = "";
for (; --n; ans = exchange(temp, ""))
for (auto i = begin(ans), e = end(ans); i != e; )
{
auto j = adjacent_find(i, e, not_equal_to{});
auto t = exchange(i, (j == e ? j : next(j)));
temp += to_string(i - t) + *t;
}
return ans;
}
};
时间复杂度:O(n * m), m 为生成的字符串中的最大长度
空间复杂度:O(m),m 为生成的字符串中的最大长度
法二:打表
参考官方题解
class Solution {
public:
string countAndSay(int n) {
vector<string> arr =
{
"","1","11","21","1211","111221","312211","13112221","1113213211","31131211131221","13211311123113112211","11131221133112132113212221","3113112221232112111312211312113211","1321132132111213122112311311222113111221131221","11131221131211131231121113112221121321132132211331222113112211","311311222113111231131112132112311321322112111312211312111322212311322113212221","132113213221133112132113311211131221121321131211132221123113112221131112311332111213211322211312113211","11131221131211132221232112111312212321123113112221121113122113111231133221121321132132211331121321231231121113122113322113111221131221","31131122211311123113321112131221123113112211121312211213211321322112311311222113311213212322211211131221131211132221232112111312111213111213211231131122212322211331222113112211","1321132132211331121321231231121113112221121321132122311211131122211211131221131211132221121321132132212321121113121112133221123113112221131112311332111213122112311311123112111331121113122112132113213211121332212311322113212221","11131221131211132221232112111312111213111213211231132132211211131221131211221321123113213221123113112221131112311332211211131221131211132211121312211231131112311211232221121321132132211331121321231231121113112221121321133112132112312321123113112221121113122113121113123112112322111213211322211312113211","311311222113111231133211121312211231131112311211133112111312211213211312111322211231131122211311122122111312211213211312111322211213211321322113311213212322211231131122211311123113223112111311222112132113311213211221121332211211131221131211132221232112111312111213111213211231132132211211131221232112111312211213111213122112132113213221123113112221131112311311121321122112132231121113122113322113111221131221","132113213221133112132123123112111311222112132113311213211231232112311311222112111312211311123113322112132113213221133122112231131122211211131221131112311332211211131221131211132221232112111312111213322112132113213221133112132113221321123113213221121113122123211211131221222112112322211231131122211311123113321112131221123113111231121113311211131221121321131211132221123113112211121312211231131122211211133112111311222112111312211312111322211213211321322113311213211331121113122122211211132213211231131122212322211331222113112211","111312211312111322212321121113121112131112132112311321322112111312212321121113122112131112131221121321132132211231131122211331121321232221121113122113121113222123112221221321132132211231131122211331121321232221123113112221131112311332111213122112311311123112112322211211131221131211132221232112111312211322111312211213211312111322211231131122111213122112311311221132211221121332211213211321322113311213212312311211131122211213211331121321123123211231131122211211131221131112311332211213211321223112111311222112132113213221123123211231132132211231131122211311123113322112111312211312111322212321121113122123211231131122113221123113221113122112132113213211121332212311322113212221","3113112221131112311332111213122112311311123112111331121113122112132113121113222112311311221112131221123113112221121113311211131122211211131221131211132221121321132132212321121113121112133221123113112221131112311332111213213211221113122113121113222112132113213221232112111312111213322112132113213221133112132123123112111311222112132113311213211221121332211231131122211311123113321112131221123113112221132231131122211211131221131112311332211213211321223112111311222112132113212221132221222112112322211211131221131211132221232112111312111213111213211231132132211211131221232112111312211213111213122112132113213221123113112221133112132123222112111312211312112213211231132132211211131221131211132221121311121312211213211312111322211213211321322113311213212322211231131122211311123113321112131221123113112211121312211213211321222113222112132113223113112221121113122113121113123112112322111213211322211312113211","1321132132211331121321231231121113112221121321133112132112312321123113112221121113122113111231133221121321132122311211131122211213211321322112312321123113213221123113112221131112311332211211131221131211132211121312211231131112311211232221121321132132211331121321231231121113121113122122311311222113111231133221121113122113121113221112131221123113111231121123222112111312211312111322212321121113121112131112132112311321322112111312212321121113122122211211232221121321132132211331121321231231121113112221121321132132211322132113213221123113112221133112132123222112111312211312112213211231132132211211131221131211322113321132211221121332211231131122211311123113321112131221123113111231121113311211131221121321131211132221123113112211121312211231131122211211133112111311222112111312211312111322211213211321322123211211131211121332211231131122211311122122111312211213211312111322211231131122211311123113322112111331121113112221121113122113111231133221121113122113121113222123211211131211121332211213211321322113311213212312311211131122211213211321223112111311222112111312211312113221133221121113122113221321132132211231131122211311123113111213211221121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};
return arr[n];
}
};
以上是关于《LeetCode之每日一题》:178.外观数列的主要内容,如果未能解决你的问题,请参考以下文章
LeetCode 剑指 Offer II 069. 山峰数组的顶部(三分) / 38. 外观数列 / 282. 给表达式添加运算符