算法：最多水容量11. Container With Most Water

Posted 2021-10-31 架构师易筋

11. Container With Most Water

Given n non-negative integers a1, a2, …, an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of the line i is at (i, ai) and (i, 0). Find two lines, which, together with the x-axis forms a container, such that the container contains the most water.

Notice that you may not slant the container.

Example 1:

Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49
Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.

Example 2:

Input: height = [1,1]
Output: 1

Example 3:

Input: height = [4,3,2,1,4]
Output: 16

Example 4:

Input: height = [1,2,1]
Output: 2

Constraints:

• n == height.length
• 2 <= n <= 105
• 0 <= height[i] <= 104

两端收紧解法

class Solution {
    public int maxArea(int[] height) {
        int l = 0;
        int r = height.length - 1;
        int area = 0;
        while (l < r) {
            area = Math.max(area, (r - l) * Math.min(height[l], height[r]));
            if (height[l] < height[r]) {
                l++;
            } else {
                r--;
            }
        }
        
        return area;
    }
}