golang：iota用法

Posted 2021-10-22 live4m

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const(
	a1 = iota	//0
	a2			//1
	a3			//2
	_			//3,但是被忽略了
	a5			//4
)

const (
	a1 = iota	//0
	a2 = 100	//100   本来应该是1,但是被人为赋值为100了,所以是100
	a3 = iota	//2
	a4			//3
)

//同一行复用iota不会使值变化.(iota的值只与常量声明的行数相关)
const (
	a1, a2 = iota, iota //0 0
	a3, a4 = iota, iota //1 1
)

const (
	a1 = (1 << iota) //1<<0 = 1
	a2 = (1 << iota) //1<<1 = 2
	a3 = (1 << iota) //1<<2 = 4
	a4 = (1 << iota) //1<<3 = 8
)
const(
	a1 = (1 << (iota+1)) //1<<(0+1) = 2
	a2 = (1 << (iota+1)) //1<<(1+1) = 4
	a3 = (1 << (iota+1)) //1<<(2+1) = 8
	a4 = (1 << (iota+1)) //1<<(3+1) = 16
)

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