C语言实现linux系统获取高精度时间差（毫秒）

Posted 2021-10-07 Hero_HL

简介

通过函数gettimeofday获取当前时间

代码

#include <stdio.h>
#include <sys/time.h>
#include <unistd.h>
int main()
{
	double dbCostms;
	struct timeval tvStart, tvEnd;

	gettimeofday(&tvStart, NULL);
	usleep(30000);
	gettimeofday(&tvEnd, NULL);
	dbCostms = (double)(1000 * (tvEnd.tv_sec - tvStart.tv_sec) + ((tvEnd.tv_usec - tvStart.tv_usec) / 1000.0));
	printf("cost %-0.2f ms\\n", dbCostms);

	gettimeofday(&tvStart, NULL);
	sleep(3);
	gettimeofday(&tvEnd, NULL);
	dbCostms = (double)(1000 * (tvEnd.tv_sec - tvStart.tv_sec) + ((tvEnd.tv_usec - tvStart.tv_usec) / 1000.0));
	printf("cost %-0.2f ms\\n", dbCostms);

	gettimeofday(&tvStart, NULL);
	sleep(20);
	gettimeofday(&tvEnd, NULL);
	dbCostms = (double)(1000 * (tvEnd.tv_sec - tvStart.tv_sec) + ((tvEnd.tv_usec - tvStart.tv_usec) / 1000.0));
	printf("cost %-0.2f ms\\n", dbCostms);

	gettimeofday(&tvStart, NULL);
	usleep(2688);
	gettimeofday(&tvEnd, NULL);
	dbCostms = (double)(1000 * (tvEnd.tv_sec - tvStart.tv_sec) + ((tvEnd.tv_usec - tvStart.tv_usec) / 1000.0));
	printf("cost %-0.2f ms\\n", dbCostms);

	getchar();
	return 0;
}

测试结果