Linux获取当前年月日后缀精确到微秒,例如2017-05-06T23:57:07.713171

Posted 2020-09-17 Paprika

代码如下：详细见注释

#include <stdio.h>
#include <string.h>
#include <time.h>
#include <sys/time.h>

int main() {
    struct timeval start;
    struct tm *local_time = NULL;
    static char str_time[100];
    char ms[16];
    gettimeofday( &start, NULL );//获取当前时间，该结构体返回Unix时间戳秒数与微秒数
    local_time = localtime(&start.tv_sec);//将秒转换标准时间
    strftime(str_time, sizeof(str_time), "%Y-%m-%dT%H:%M:%S", local_time);
    sprintf(ms,".%ld",start.tv_usec);
    strcat(str_time,ms);//将毫秒附着在时间后
    printf("time: %s \n", str_time);
    return 0;
}