LeetCode Length of Last Word

Posted liguangsunls

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了LeetCode Length of Last Word相关的知识,希望对你有一定的参考价值。

1. 题目


Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.


2.解决方式


class Solution {
public:
    int lengthOfLastWord(const char *s) {
        int len = strlen(s);
        int result = 0;
        
        while(s[len-1]==‘ ‘) len--;
        
        for(int i = len - 1; i >= 0; --i){
            if(s[i] != ‘ ‘){
                ++result;
            }else{
                    break;
            }
        }
        return result;
        }
        
    
};

思路:还是比較easy的,就是要先把后面的‘ ’都先干掉。

http://www.waitingfy.com/archives/1645








以上是关于LeetCode Length of Last Word的主要内容,如果未能解决你的问题,请参考以下文章

LeetCode:Length of Last Word

一天一道LeetCode#58. Length of Last Word

Java [Leetcode 58]Length of Last Word

LeetCode Length of Last Word

Leetcode 之Length of Last Word(36)

Length of last word--LeetCode