题目1082:代理服务器(贪心算法)
Posted 伊甸一点
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了题目1082:代理服务器(贪心算法)相关的知识,希望对你有一定的参考价值。
题目链接:http://ac.jobdu.com/problem.php?pid=1082
详解链接:https://github.com/zpfbuaa/JobduInCPlusPlus
参考代码:
// // 1082 代理服务器.cpp // Jobdu // // Created by PengFei_Zheng on 03/05/2017. // Copyright © 2017 PengFei_Zheng. All rights reserved. // #include <stdio.h> #include <iostream> #include <algorithm> #include <string.h> #include <cstring> #include <cmath> #include <climits> #define MAX_SIZE 1001 #define MAX_SERVER 5001 //#define debug using namespace std; int n, m; struct Server{//define the struct of server int x, y, z, w; bool operator == (const Server &a) const{//reload the == operator return (x==a.x && y==a.y && z==a.z && w==a.w); } }; Server s1[MAX_SIZE]; Server s2[MAX_SERVER]; int main(){ #ifdef debug freopen("/Users/pengfei_zheng/Desktop/input.txt", "r", stdin); #endif while(scanf("%d",&n)!=EOF){ for(int i = 0 ; i < n ; i++){ scanf("%d.%d.%d.%d",&s1[i].x,&s1[i].y,&s1[i].z,&s1[i].w); } scanf("%d",&m); for(int i = 0 ; i < m ; i++){ scanf("%d.%d.%d.%d",&s2[i].x,&s2[i].y,&s2[i].z,&s2[i].w); } if(1==n){//special case int i; for(i = 0 ; i < m ; i++){ if(s1[0]==s2[i]){ break; } } if(i<m) printf("-1\n"); else printf("0\n"); } else{ bool loopFlag = true; int start=0, ans = 0, idx = 0; int maxIdx; while(loopFlag){ maxIdx = -1; loopFlag = false; for(int i = 0 ; i < n ; i++){ idx = start; while(idx < m && !(s1[i]==s2[idx])){ idx++; } maxIdx = max(maxIdx,idx);// find the last appear server } if(maxIdx < m){ //judge whether this server can reach all the other servers ans++; loopFlag = true; } start = maxIdx + 1; //update the start Idx } printf("%d\n",ans); } } return 0; } /************************************************************** Problem: 1082 User: zpfbuaa Language: C++ Result: Accepted Time:10 ms Memory:1612 kb ****************************************************************/
以上是关于题目1082:代理服务器(贪心算法)的主要内容,如果未能解决你的问题,请参考以下文章