Leetcode 1340. Jump Game V

Posted SnailTyan

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Leetcode 1340. Jump Game V相关的知识,希望对你有一定的参考价值。

文章作者:Tyan
博客:noahsnail.com  |  CSDN  |  简书

1. Description

2. Solution

**解析:**Version 1,采用深度优先搜索,使用visited记录遍历过的索引及对应的跳跃次数,如果当前索引遍历过,直接返回对应的跳跃次数,分别遍历其左右两侧,取左右两侧最大的跳跃次数,返回最大跳跃次数加上当前元素的跳跃次数1。Version 2对数组先排序,获得排序后的索引,然后从最小值的索引开始寻找左右两侧最大跳跃次数,这样每个数左右两侧比其小的数的跳跃次数都已计算出来,所有元素的初始默认跳跃次数为1,依次更新dp[current],最后返回最大跳跃次数。

  • Version 1
class Solution:
    def maxJumps(self, arr: List[int], d: int) -> int:
        stat = {}
        n = len(arr)
        visited = {}
        nums = 0
        for i in range(n):
            nums = max(nums, self.dfs(arr, i, visited, d))
        return nums


    def dfs(self, arr, current, visited, d):
        if current in visited:
            return visited[current]
        n = len(arr)
        count = 0
        i = current - 1
        thres = max(-1, current - d - 1)
        while i > thres and arr[i] < arr[current]:
            temp = self.dfs(arr, i, visited, d)
            visited[i] = temp
            count = max(count, temp)
            i -= 1
        i = current + 1
        thres = min(n, current + d + 1)
        while i <  thres and arr[i] < arr[current]:
            temp = self.dfs(arr, i, visited, d)
            visited[i] = temp
            count = max(count, temp)
            i += 1
        return count + 1
  • Version 2
class Solution:
    def maxJumps(self, arr: List[int], d: int) -> int:
        indexes = sorted(range(len(arr)), key=lambda i: arr[i])
        n = len(arr)
        dp = [1] * n
        nums = 0
        for current in indexes:
            i = current - 1
            thres = max(-1, current - d - 1)
            count = 0
            while i > thres and arr[i] < arr[current]:
                count = max(count, dp[i])
                i -= 1
            i = current + 1
            thres = min(n, current + d + 1)
            while i < thres and arr[i] < arr[current]:
                count = max(count, dp[i])
                i += 1
            dp[current] += count
            nums = max(nums, dp[current])
        return nums

Reference

  1. https://leetcode.com/problems/jump-game-v/

以上是关于Leetcode 1340. Jump Game V的主要内容,如果未能解决你的问题,请参考以下文章

LC 1340. Jump Game V

LeetCode 55. Jump Game

[LeetCode]Jump Game

LeetCode OJ 55. Jump Game

Leetcode55 Jump Game

Leetcode 55. Jump Game