扫雷游戏，一雷不扫何以扫天下

Posted 2021-08-31 再吃一个橘子

TDD游戏测试部分

test.c

#define _CRT_SECURE_NO_WARNINGS
#include"game.h"
void menu()
{
	printf("**************************\\n");
	printf("******   1.play   ********\\n");
	printf("******   2.exit   ********\\n");
	printf("**************************\\n");
}

void game()
{
	char mine[ROWS][COLS] = { 0 };//存放雷的信息
	char show[ROWS][COLS] = { 0 };//存放排查出的雷的信息
	//初始化棋盘
	InitBoard(mine,ROWS,COLS,'0');//'0'
	InitBoard(show, ROWS, COLS,'*');//'*'

	//布置雷
	SetMine(mine, ROW, COL);
	//DisplayBoard(mine, ROW, COL);
	DisplayBoard(show, ROW, COL);

	//排查雷
	FindMine(mine, show, ROW, COL);
}
int main()
{
	int input = 0;
	do
	{
		srand((unsigned int)time(NULL));
		menu();
		printf("请选择：>");
		scanf("%d", &input);
		switch (input)
		{
		case 1:
			game();
			break;
		case 0:
			printf("退出游戏\\n");
			break;
		default:
			printf("选择错误，重新选择：\\n");
			break;
		}
	} while (input);
}

游戏实现game.c

#define _CRT_SECURE_NO_WARNINGS

#include"game.h"

//初始化棋盘
void InitBoard(char board[ROWS][COLS], int rows, int cols,char set)
{
	int i = 0;
	for (i = 0; i < rows; i++)
	{
		int j = 0;
		for (j = 0; j < cols; j++)
		{
			board[i][j] = set;
		}
	}
}

//显示棋盘
void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
	int i = 0;
	printf("---------------------------------\\n");
	for (i = 0; i <= col; i++)
	{
		printf("%d ", i);
	}
	printf("\\n");
	for (i = 1; i <= row; i++)
	{
		printf("%d ", i);
		int j = 0;
		for (j = 1; j <= col; j++)
		{
			printf("%c ", board[i][j]);
		}
		printf("\\n");
	}
	printf("---------------------------------\\n");
}

//布置雷
void SetMine(char board[ROWS][COLS], int row, int col)
{
	int count = EASY_COUNT;
	while (count)
	{
		//1.生成随机下标
		int x = rand() % row + 1;
		int y = rand() % col + 1;

		if (board[x][y] != '1')
		{
			board[x][y] = '1';
			count--;
		}
	}
}

//获取到某个位置周围雷的个数
int GetMineCount(char mine[ROWS][COLS], int x, int y)
{
	return (mine[x - 1][y - 1] +
		mine[x - 1][y] +
		mine[x - 1][y + 1] +
		mine[x][y - 1] +
		mine[x][y + 1] +
		mine[x + 1][y - 1] +
		mine[x + 1][y] +
		mine[x + 1][y + 1] - 8 * '0');
}
//排查雷
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x = 0;
	int y = 0;
	int win = 0;
	while (win <= row * col - EASY_COUNT)
	{
		printf("请输入要排查的坐标：>");
		scanf("%d %d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
			if (mine[x][y] == '1')
			{
				printf("很遗憾，你被炸死了~");
				DisplayBoard(mine, ROW, COL);
				break;
			}
			else
			{
				int count = GetMineCount(mine, row, col);
				show[x][y] = count + '0';//'3'-'0' = 3
				DisplayBoard(show, ROW, COL);
				win++;
			}
		}
		else
		{
			printf("坐标非法，请重新输入：>");
		}
	}
	if (win == row * col - EASY_COUNT)
	{
		printf("恭喜你，排雷成功！\\n");
		DisplayBoard(mine, ROW, COL);
	}
}

函数声明，game.h

#pragma once

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#define ROW 9
#define COL 9

#define ROWS ROW+2
#define COLS COL+2

#define EASY_COUNT 10//简单版本雷的个数( 10个 )

//初始化棋盘
void InitBoard(char board[ROWS][COLS], int rows,int cols,char set);

//显示棋盘
void DisplayBoard(char board[ROWS][COLS], int row, int col);

//布置雷
void SetMine(char board[ROWS][COLS], int row, int col);

//排查雷
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);