C++实现两个线程交替打印奇偶数

Posted 2021-08-21 _BitterSweet

#include<iostream>
#include<mutex>
#include<thread>
#include<condition_variable>
#include<Windows.h>
using namespace std;

mutex mut;
condition_variable cond1, cond2;
int g_nums = 1;


//线程1
void thread1()
{
	while (1)
	{
		unique_lock<mutex> locker(mut);
		cout << "Thread1:" << g_nums << endl;
		g_nums++;
		cond2.notify_one();
		cond1.wait(locker);
		locker.unlock();
		Sleep(1000);
	}
}

//线程2
void thread2()
{
	while (1)
	{
		Sleep(1000);
		unique_lock<mutex> locker(mut);
		cout << "Thread2:" << g_nums << endl;
		g_nums++;
		cond1.notify_one();
		cond2.wait(locker);
		locker.unlock();
	}
}
int main()
{
	thread t1(thread1);
	thread t2(thread2);
	t1.join();
	t2.join();
	system("pause");
	return 0;
}