nowcoder网络流小Y写文章
Posted kaka0010
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原题链接:https://ac.nowcoder.com/acm/problem/15600
题意
分析
求最大值的最小值问题,自然想到二分答案。然后就是建图跑网络流,我最开始的想法是m个段落去匹配n+1个空位,最后看流量是否满足m。很快就被证明是错误的,因为这样不能保证剩下n-m+1个空位是满足要求的。
既然要让n+1个位置都满足要求,那么必须让n+1个空位对m个段落匹配,但发现m肯定小于n,因此需要再用上一些本来就符合要求的段落作为虚点。如果你这个空位本来就符合要求,你可以向n-m+1个虚点连边,如果在插入段落之后满足要求,你可以向m个段落连边,最后跑一遍最大流,流量是n+1就符合要求。
Code
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> PII;
const ll INF = 1e9;
const int N = 400 + 10;
const int M = 3e6 + 10;
const int MOD = 1e9 + 7;
int st, ed;
struct Maxflow {
int h[N], cnt, maxflow, deep[N], cur[N];
struct Edge {
int to, next;
ll cap;
} e[M<<1];
void init() {
memset(h, -1, sizeof h);
cnt = maxflow = 0;
}
void add(int u, int v, int cap) {
e[cnt].to = v;
e[cnt].cap = cap;
e[cnt].next = h[u];
h[u] = cnt++;
e[cnt].to = u;
e[cnt].cap = 0;
e[cnt].next = h[v];
h[v] = cnt++;
}
bool bfs() {
for (int i = 0; i <= ed; i++) deep[i] = -1, cur[i] = h[i];
queue<int> q; q.push(st); deep[st] = 0;
while (q.size()) {
int u = q.front();
q.pop();
for (int i = h[u]; ~i; i = e[i].next) {
int v = e[i].to;
if (e[i].cap && deep[v] == -1) {
deep[v] = deep[u] + 1;
q.push(v);
}
}
}
if (deep[ed] >= 0) return true;
else return false;
}
ll dfs(int u, ll mx) {
ll a;
if (u == ed) return mx;
for (int i = cur[u]; ~i; i = e[i].next) {
cur[u] = i;//优化
int v = e[i].to;
if (e[i].cap && deep[v] == deep[u] + 1 && (a = dfs(v, min(e[i].cap, mx)))) {
e[i].cap -= a;
e[i ^ 1].cap += a;
return a;
}
}
return 0;
}
void dinic() {
ll res;
while (bfs()) {
while (1) {
res = dfs(st, INF);
if (!res) break;
maxflow += res;
}
}
}
}mf;
int a[N], b[N];
void solve() {
int T; cin >> T; while (T--) {
int n, m; cin >> n >> m;
for (int i = 1; i <= n; i++) cin >> a[i];
for (int i = 1; i <= m; i++) cin >> b[i];
st = 2 * n + 2; ed = 2 * n + 3;
int l = 1, r = 1e9;
while (l <= r) {
int mid = (l + r) >> 1;
mf.init();
for (int i = 0; i <= n; i++) mf.add(st, i, 1);
for (int i = n+1; i <= 2*n+1; i++) mf.add(i, ed, 1);
for (int i = 0; i <= n; i++) {
if (i == 0) {
for (int j = n+m+1; j <= 2*n+1; j++) mf.add(i, j, 1);
for (int j = 1; j <= m; j++) {
if (abs(b[j] - a[1]) <= mid) mf.add(i, j+n, 1);
}
} else if (i == n) {
for (int j = n+m+1; j <= 2*n+1; j++) mf.add(i, j, 1);
for (int j = 1; j <= m; j++) {
if (abs(b[j] - a[n]) <= mid) mf.add(i, j+n, 1);
}
} else {
for (int j = n+m+1; j <= 2*n+1; j++) {
if (abs(a[i+1]-a[i]) <= mid) mf.add(i, j, 1);
}
for (int j = 1; j <= m; j++) {
if (abs(b[j] - a[i]) <= mid && abs(b[j] - a[i+1]) <= mid) mf.add(i, j+n, 1);
}
}
}
mf.dinic();
if (mf.maxflow >= n+1) r = mid - 1;
else l = mid + 1;
}
cout << l << endl;
}
}
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
#ifdef ACM_LOCAL
freopen("input", "r", stdin);
freopen("output", "w", stdout);
signed test_index_for_debug = 1;
char acm_local_for_debug = 0;
do {
if (acm_local_for_debug == '$') exit(0);
if (test_index_for_debug > 20)
throw runtime_error("Check the stdin!!!");
auto start_clock_for_debug = clock();
solve();
auto end_clock_for_debug = clock();
cout << "Test " << test_index_for_debug << " successful" << endl;
cerr << "Test " << test_index_for_debug++ << " Run Time: "
<< double(end_clock_for_debug - start_clock_for_debug) / CLOCKS_PER_SEC << "s" << endl;
cout << "--------------------------------------------------" << endl;
} while (cin >> acm_local_for_debug && cin.putback(acm_local_for_debug));
#else
solve();
#endif
return 0;
}
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