Codeforces Round #595 (Div. 3) F. Maximum Weight Subset 树形dp
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原题链接:https://codeforces.com/problemset/problem/1249/F
题意
有一颗树,每个节点都有权值,在树上选择距离大于k且选取集合权值和最大是多少。
分析
因为要选择大于k距离的点对,因此状态必须记录在子节点中距离大于j的最大权值,那么状态就可以直接出来了。我们设 f [ i ] [ j ] f[i][j] f[i][j]代表以i为根的子树中,距离大于j的最大权值。
分类讨论一下
- j = = 0 时 , f [ i ] [ 0 ] = a [ i ] + d p [ v ] [ k ] , v ∈ i 的 子 节 点 j==0时,f[i][0]=a[i]+dp[v][k],v∈i的子节点 j==0时,f[i][0]=a[i]+dp[v][k],v∈i的子节点
- j > 0 时 , f [ i ] [ j ] = a [ i ] + m a x ( d p [ v 1 ] [ m a x ( j − 1 , k − j ) ] + d p [ v 2 ] [ j − 1 ] ) j ∈ [ 1 , n ) j>0时,f[i][j]=a[i]+max(dp[v1][max(j-1,k-j)]+dp[v2][j-1])j∈[1,n) j>0时,f[i][j]=a[i]+max(dp[v1][max(j−1,k−j)]+dp[v2][j−1])j∈[1,n)
最后不要忘记从后往前取一遍max,因为我们的状态为大于j的最大权值,也就是说前面的状态是包含后面的状态的,因此后面的状态不要忘了更新前面的状态。
Code
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> PII;
const ll INF = 1e18;
const int N = 4e5 + 10;
const int M = 1000010;
const int MOD = 1e9 + 7;
int a[205];
int n, k;
ll dp[205][205];
vector<int> g[205];
void dfs(int x, int fa) {
dp[x][0] = a[x];
for (auto v : g[x]) {
if (v == fa) continue;
dfs(v, x);
dp[x][0] += dp[v][k];
}
for (int i = 1; i < n; i++) {
for (auto v1 : g[x]) {
if (v1 == fa) continue;
ll tmp = dp[v1][i-1];
for (auto v2 : g[x]) {
if (v2 == fa || v2 == v1) continue;
tmp += dp[v2][max(i-1, k-i)];
}
dp[x][i] = max(dp[x][i], tmp);
}
}
for (int i = n-1; i >= 0; i--) dp[x][i] = max(dp[x][i], dp[x][i+1]);
}
void solve () {
cin >> n >> k;
for (int i = 1; i <= n; i++) cin >> a[i];
for (int i = 1; i <= n-1; i++) {
int u, v; cin >> u >> v;
g[u].push_back(v);
g[v].push_back(u);
}
dfs(1, 0);
cout << dp[1][0] << endl;
}
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
#ifdef ACM_LOCAL
freopen("input", "r", stdin);
freopen("output", "w", stdout);
signed test_index_for_debug = 1;
char acm_local_for_debug = 0;
do {
if (acm_local_for_debug == '$') exit(0);
if (test_index_for_debug > 20)
throw runtime_error("Check the stdin!!!");
auto start_clock_for_debug = clock();
solve();
auto end_clock_for_debug = clock();
cout << "Test " << test_index_for_debug << " successful" << endl;
cerr << "Test " << test_index_for_debug++ << " Run Time: "
<< double(end_clock_for_debug - start_clock_for_debug) / CLOCKS_PER_SEC << "s" << endl;
cout << "--------------------------------------------------" << endl;
} while (cin >> acm_local_for_debug && cin.putback(acm_local_for_debug));
#else
solve();
#endif
return 0;
}
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