leetcode : Length of Last Word [基本功]
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Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
思路: 两根指针
(1) 先从右往左判断是否有空
(2)移动左指针
(3) 右指针 - 左指针
public class Solution { public int lengthOfLastWord(String s) { if(s == null || s.length() == 0) { return 0; } int start = 0; int end = s.length() - 1; while(end >= 0 && s.charAt(end) == ‘ ‘) { end --; } start = end; while(start >= 0 && s.charAt(start) != ‘ ‘) { start--; } return end - start ; } }
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