Beautiful Sets of Points CodeForces

Posted 2021-07-01 acmloser

原题链接
考察:构造
思路:
  可以发现(i,i)点彼此距离为sqrt(2).我们构造彼此距离差1的点即可

Code

#include <iostream> 
#include <cstring>
using namespace std;
int n,m;
int main()
{
	while(scanf("%d%d",&n,&m)!=EOF)
	{
		int s = min(n+1,m+1);
		printf("%d\\n",s);
		for(int i=0;i<s;i++)
		  printf("%d %d\\n",i,s-i-1);
	}
	return 0;
}