集合操作
Posted 20203246
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了集合操作相关的知识,希望对你有一定的参考价值。
https://ac.nowcoder.com/acm/contest/11173/C
#include <bits/stdc++.h> using namespace std; #define int long long using LL = long long; template <typename T>void read(T &x){ x=0;T f=1; char ch=getchar(); while(!isdigit(ch)){ if(ch==\'-\')f=-1;ch=getchar(); } while(isdigit(ch)){ x=(x<<3)+(x<<1)+ch-\'0\';ch=getchar(); } x*=f; } template <typename T>void print(T x){ if(x<0){ putchar(\'-\');x=-x; } if(x>9)print(x/10);putchar(x%10+\'0\'); } template <typename T>T Abs(T x){ return x>0?x:-x; } const int Maxn = 1e6; const LL Maxr = 1e18; int n; LL k, p; LL a[Maxn + 5],tema[Maxn + 5]; bool check (LL x) { LL temp = a[n] - x * p; LL sum = 0; for (int i = 1; i <= n; i++){ if (a[i] <= temp) continue; sum += (a[i] - temp) / p; } return sum >= k; } struct Node { int idx; LL val; Node () {} Node (int IDX,LL VAL) { idx=IDX; val=VAL; } bool operator < (const Node &x) const { return val > x.val; } }; priority_queue <Node> q; void solve(LL x) { LL temp=a[n] - x * p; LL sum = 0; for (int i = 1; i <= n; i++) { if (a[i] < temp) continue; sum += (a[i] - temp) / p; a[i] -= (a[i] - temp) / p * p; q.push (Node (i, a[i])); } for (int i=1; i <= sum - k; i++) { Node tem = q.top(); q.pop (); while(a[tem.idx] + p > tema[tem.idx]) { tem = q.top(); q.pop(); } a[tem.idx] += p; tem.val += p; q.push (tem); } sort (a + 1, a + 1 + n); for(int i = 1; i <= n; i++) { print(a[i]); putchar(\' \'); } } signed main() { read (n); read (k); read (p); for (int i = 1; i <= n; i++) { read (a[i]); } sort (a + 1, a + 1 + n); memcpy(tema, a, sizeof a); if (p == 0) { for (int i = 1; i <= n; i++) printf("%lld ", a[i]); return 0; } LL l =0 , r = Maxr * 2 / p; while (l + 1 < r){ LL mid = l + r >> 1; if (check (mid)) r = mid; else l = mid; } if(check (l)) solve (l); else solve (r); return 0; }
以上是关于集合操作的主要内容,如果未能解决你的问题,请参考以下文章