如何在godaddy服务器上传图像数组？

Posted 2021-04-25

我编写代码因为我需要将多个图像上传到我的网站以显示一些细节。我正在将我的网站设置为godaddy服务器并且发生了一些错误，但是上传多个图像的这个错误无效。它适用于localhost。这是我得到的错误：

[28-Mar-2019 03:18:43 UTC] php警告：move_uploaded_file（）：copy（）函数的第二个参数不能是第123行/home/v1pyvnw05stp/public_html/**.php中的目录[28- Mar-2019 03:18:43 UTC] PHP警告：move_uploaded_file（）：无法移动;

当我查看文件夹时，我注意到他们不应该在一个地方至少有两个图像，而是作为test / x-generic文件

  $photocount = count($_FILES['photo']['name']);
  if ($photocount > 0) {
for($i = 0; $i<$photocount;$i++){
  $name = $_FILES['photo']['name'][$i];
  $nameArray = explode('.',$name);
  $filename=$nameArray[0];
  $fileExt = $nameArray[1];
  $mime = explode('/',$_FILES['photo']['type'][$i]);
  $mimeType = $mime[0];
  $mimeExt = $mime[1];
  $tmpLoc[] = $_FILES['photo']['tmp_name'][$i];
  $fileSize = $_FILES['photo']['size'][$i];
  $uploadName = md5(microtime().$i).'.'.$fileExt;
  $uploadPath = '/home/v1pyvnw05stp/public_html/images/Articulos/'.$uploadName;
  if($i != 0){
    $dbpath .= ',';
  }
  $dbpath = '/images/Articulos/'.$uploadName;


  if($photocount > 0){
      for($i = 0;$i<$photocount;$i++){
    move_uploaded_file($tmpLoc[$i],$uploadPath[$i]); THIS IS THE ERROR LINE AND IF I ERASE $I OF $UPLOADPAH THE SISTEM WORK BUT JUST WITH ONE IMAGE.
  }
}

我已经改变了许可

答案

您在move_uploaded_file()方法中传递错误参数时遇到错误。第二个arg $uploadPath[$i]不是数组，而是代码中定义的字符串。进行以下更改，

$photocount = count($_FILES['photo']['name']);
  if ($photocount > 0) {
for($i = 0; $i<$photocount;$i++){
  $name = $_FILES['photo']['name'][$i];
  $nameArray = explode('.',$name);
  $filename=$nameArray[0];
  $fileExt = $nameArray[1];
  $mime = explode('/',$_FILES['photo']['type'][$i]);
  $mimeType = $mime[0];
  $mimeExt = $mime[1];
  $tmpLoc[] = $_FILES['photo']['tmp_name'][$i];
  $fileSize = $_FILES['photo']['size'][$i];
  $uploadName = md5(microtime().$i).'.'.$fileExt;
  $uploadPath = '/home/v1pyvnw05stp/public_html/images/Articulos/'.$uploadName;
  if($i != 0){
    $dbpath .= ',';
  }
  $dbpath = '/images/Articulos/'.$uploadName;


  if($photocount > 0){
      for($i = 0;$i<$photocount;$i++){
    move_uploaded_file($tmpLoc[$i],$uploadPath);
  }
}

另一答案

不要使用服务器目录的绝对路径。

替换$ uploadPath ='/ home / v1pyvnw05stp / public_html / images / Articulos /'。$ upload;使用$ _SERVER ['DOCUMENT_ROOT']。'images / Articulos /'.$ uploadName;

用move_uploaded_file($tmpLoc[$i],$uploadPath[$i]);替换

move_uploaded_file（$ tmpLoc [$ i]于，$ uploadPath）;

另一答案

我弄明白为什么我得到了这个错误，因为我应该将[]添加到$ uploadpath。现在我没有收到错误，但是我不能在数据库中添加多个$ dbpath。一些想法为什么？

$uploadPath**[]** = '/home/v1pyvnw05stp/public_html/images/Articulos/'.$uploadName;
  if($photocount > 0){
  for($i = 0;$i<$photocount;$i++){
move_uploaded_file($tmpLoc[$i],$uploadPath[$i]);

}