嵌入与api平台的关系

Posted 2021-03-28

我怀疑Api平台。 （https://api-platform.com）我有两个实体。问题和答案。我想要一个POST调用来创建一个答案的问题。我展示了我的实体。

namespace AppEntity;

use ApiPlatformCoreAnnotationApiResource;
use DoctrineCommonCollectionsArrayCollection;
use DoctrineORMMapping as ORM;
use SymfonyComponentValidatorConstraints as Assert;
use SymfonyComponentSerializerAnnotationGroups;

/**
 * @ApiResource(
 *     normalizationContext={"groups"={"question"}},
 *     denormalizationContext={"groups"={"question"}})
 * @ORMEntity
 */
class Question
{
    /**
     * @Groups({"question"})
     * @ORMId
     * @ORMGeneratedValue
     * @ORMColumn(type="integer")
     */
    private $id;

    /**
     * @Groups({"question"})
     * @ORMColumn
     * @AssertNotBlank
     */
    public $name = '';

    /**
     * @Groups({"question"})
     * @ORMOneToMany(targetEntity="Answer", mappedBy="question", cascade={"persist"})
     */
    private $answers;

    public function getAnswers()
    {
        return $this->answers;
    }

    public function setAnswers($answers): void
    {
        $this->answers = $answers;
    }


    public function __construct() {
        $this->answers = new ArrayCollection();
    }

    public function getName(): string
    {
        return $this->name;
    }

    public function setName(string $name): void
    {
        $this->name = $name;
    }

    public function getId(): int
    {
        return $this->id;
    }
}

和答案实体

namespace AppEntity;

use ApiPlatformCoreAnnotationApiResource;
use DoctrineORMMapping as ORM;
use SymfonyComponentValidatorConstraints as Assert;
use SymfonyComponentSerializerAnnotationGroups;

/**
 *
 * @ApiResource
 * @ORMEntity
 */
class Answer
{
    /**
     * @Groups({"question"})
     * @ORMId
     * @ORMColumn(type="guid")
     */
    public $id;

    /**
     * @Groups({"question"})
     * @ORMColumn
     * @AssertNotBlank
     */
    public $name = '';

    /**
     * @ORMManyToOne(targetEntity="Question", inversedBy="answers")
     * @ORMJoinColumn(name="question_id", referencedColumnName="id")
     */
    public $question;

    public function getQuestion()
    {
        return $this->question;
    }

    public function setQuestion($question): void
    {
        $this->question = $question;
    }

    public function getName(): string
    {
        return $this->name;
    }

    public function setName(string $name): void
    {
        $this->name = $name;
    }

    public function getId(): string
    {
        return $this->id;
    }

    public function __toString()
    {
        return $this->getName();
    }
}

现在我可以从nelmio的仪表板创建一个问题并回答答案。但是在数据库中，我的答案并没有保存与问题的关系。

{
  "name": "my new question number 1",
  "answers": [
    {
          "id": "ddb66b71-5523-4158-9aa3-2691cae9d473",
          "name": "my answer 1 to question number 1"
    }
  ]
}

还有一个问题是......我用一个guid改变了我的回答ID，因为当我创建并在没有id的情况下回答问题时，我得到了错误。我可以创建一个问题，而无需指定ID即可回答问题吗？

提前致谢

答案

对于第一点，它应该在数据库中持久存在而没有问题。无论如何，您可以为Question实体创建一个PostValidateSubscriber并检查是否存在关系。

<?php /** @noinspection PhpUnhandledExceptionInspection */

namespace AppEventSubscriber;

use ApiPlatformCoreEventListenerEventPriorities;
use SymfonyComponentEventDispatcherEventSubscriberInterface;
use SymfonyComponentHttpFoundationRequest;
use SymfonyComponentHttpKernelEventGetResponseForControllerResultEvent;
use SymfonyComponentHttpKernelKernelEvents;
use SymfonyComponentSecurityCoreAuthenticationTokenStorageTokenStorageInterface;

final class QuestionPostValidateSubscriber implements EventSubscriberInterface
{
    private $tokenStorage;

    public function __construct(
        TokenStorageInterface $tokenStorage
    ) {
        $this->tokenStorage = $tokenStorage;
    }
    /**
     * {@inheritdoc}
     */
    public static function getSubscribedEvents()
    {
        return [
            KernelEvents::VIEW => ['checkQuestionData', EventPriorities::POST_VALIDATE]
        ];
    }

    /**
     * @param GetResponseForControllerResultEvent $event
     */
    public function checkQuestionData(GetResponseForControllerResultEvent $event)
    {
        $bid = $event->getControllerResult();
        $method = $event->getRequest()->getMethod();

        if (!$question instanceof Question || (Request::METHOD_POST !== $method && Request::METHOD_PUT !== $method))
            return;

        $currentUser = $this->tokenStorage->getToken()->getUser();
        if (!$currentUser instanceof User)
            return;
    }
}

并做一个回声或使用xdebug检查问题。

对于第二点，您可以为实体的id添加这些注释，因此id将生成自己的ID。

• @ORM GeneratedValue（）
• @ORM 柱（类型= “整数”）