leetcode-42-接雨水
Posted 真不知道叫啥好
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了leetcode-42-接雨水相关的知识,希望对你有一定的参考价值。
题目描述:
第一次提交:
class Solution: def trap(self, height: List[int]) -> int: res = 0 def helper(height): nonlocal res if len(height) <= 1: return queue = [] for i in height: if queue and i >= queue[0]: res += sum(queue[0] - j for j in queue) queue = [i] else: queue.append(i) helper(queue[::-1]) helper(height) return res
方法一:动态规划: O(N) O(N)
class Solution: def trap(self, height: List[int]) -> int: if not height: return 0 n = len(height) max_left = [0] * n max_right = [0] * n max_left[0] = height[0] max_right[-1] = height[-1] # 找位置i左边最大值 for i in range(1, n): max_left[i] = max(height[i], max_left[i-1]) # 找位置i右边最大值 for i in range(n-2, -1, -1): max_right[i] = max(height[i], max_right[i+1]) #print(max_left) #print(max_right) # 求结果 res = 0 for i in range(n): res += min(max_left[i], max_right[i]) - height[i] return res
方法二:双指针 O(N) O(1)
class Solution: def trap(self, height: List[int]) -> int: if not height: return 0 left = 0 right = len(height) - 1 res = 0 # 记录左右边最大值 left_max = height[left] right_max = height[right] while left < right: if height[left] < height[right]: if left_max > height[left]: res += left_max - height[left] else: left_max = height[left] left += 1 else: if right_max > height[right]: res += right_max - height[right] else: right_max = height[right] right -= 1 return res
方法三:栈 O(N)*
class Solution: def trap(self, height: List[int]) -> int: if not height: return 0 n = len(height) stack = [] res = 0 for i in range(n): #print(stack) while stack and height[stack[-1]] < height[i]: tmp = stack.pop() if not stack: break res += (min(height[i], height[stack[-1]]) - height[tmp]) * (i-stack[-1] - 1) stack.append(i) return res
以上是关于leetcode-42-接雨水的主要内容,如果未能解决你的问题,请参考以下文章