LeetCode - Fizz Buzz Multithreaded
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Write a program that outputs the string representation of numbers from 1 to n, however: If the number is divisible by 3, output "fizz". If the number is divisible by 5, output "buzz". If the number is divisible by both 3 and 5, output "fizzbuzz". For example, for n = 15, we output: 1, 2, fizz, 4, buzz, fizz, 7, 8, fizz, buzz, 11, fizz, 13, 14, fizzbuzz. Suppose you are given the following code: class FizzBuzz { public FizzBuzz(int n) { ... } // constructor public void fizz(printFizz) { ... } // only output "fizz" public void buzz(printBuzz) { ... } // only output "buzz" public void fizzbuzz(printFizzBuzz) { ... } // only output "fizzbuzz" public void number(printNumber) { ... } // only output the numbers } Implement a multithreaded version of FizzBuzz with four threads. The same instance of FizzBuzz will be passed to four different threads: Thread A will call fizz() to check for divisibility of 3 and outputs fizz. Thread B will call buzz() to check for divisibility of 5 and outputs buzz. Thread C will call fizzbuzz() to check for divisibility of 3 and 5 and outputs fizzbuzz. Thread D will call number() which should only output the numbers.
class FizzBuzz { private int n; private volatile int count = 1; public FizzBuzz(int n) { this.n = n; } // printFizz.run() outputs "fizz". public void fizz(Runnable printFizz) throws InterruptedException { synchronized(this){ while (count <= n) { if(count % 3 == 0 && count % 5 != 0) { printFizz.run(); count++; this.notifyAll(); } else { this.wait(); } } } } // printBuzz.run() outputs "buzz". public void buzz(Runnable printBuzz) throws InterruptedException { synchronized(this){ while (count <= n) { if(count % 5 == 0 && count % 3 != 0) { printBuzz.run(); count++; this.notifyAll(); } else { this.wait(); } } } } // printFizzBuzz.run() outputs "fizzbuzz". public void fizzbuzz(Runnable printFizzBuzz) throws InterruptedException { synchronized(this){ while (count <= n) { if(count % 5 == 0 && count % 3 == 0) { printFizzBuzz.run(); count++; this.notifyAll(); } else { this.wait(); } } } } // printNumber outputs "x", where x is an integer. public void number(IntConsumer printNumber) throws InterruptedException { synchronized(this){ while (count <= n) { if(count % 5 != 0 && count % 3 != 0) { printNumber.accept(count); count++; this.notifyAll(); } else { this.wait(); } } } } }
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