leetcode刷题记录——栈和队列

Posted 2021-02-20 xiuzhublog

题目

232.用栈实现队列

class MyQueue {

    private Stack<Integer> in = new Stack<>();
    private Stack<Integer> out = new Stack<>();

    public void push(int x) {
        in.push(x);
    }

    public int pop() {
        in2out();
        return out.pop();
    }

    public int peek() {
        in2out();
        return out.peek();
    }

    private void in2out() {
        if (out.isEmpty()) {
            while (!in.isEmpty()) {
                out.push(in.pop());
            }
        }
    }

    public boolean empty() {
        return in.isEmpty() && out.isEmpty();
    }
}

225.用队列实现栈

class MyStack {

    private Queue<Integer> queue;

    public MyStack() {
        queue = new LinkedList<>();
    }

    public void push(int x) {
        queue.add(x);
        int cnt = queue.size();
        while (cnt-- > 1) {
            queue.add(queue.poll());
        }
    }

    public int pop() {
        return queue.remove();
    }

    public int top() {
        return queue.peek();
    }

    public boolean empty() {
        return queue.isEmpty();
    }
}

155.最小栈

class MinStack {

    private Stack<Integer> dataStack;
    private Stack<Integer> minStack;
    private int min;

    public MinStack() {
        dataStack = new Stack<>();
        minStack = new Stack<>();
        min = Integer.MAX_VALUE;
    }

    public void push(int x) {
        dataStack.add(x);
        min = Math.min(min, x);
        minStack.add(min);
    }

    public void pop() {
        dataStack.pop();
        minStack.pop();
        min = minStack.isEmpty() ? Integer.MAX_VALUE : minStack.peek();
    }

    public int top() {
        return dataStack.peek();
    }

    public int getMin() {
        return minStack.peek();
    }
}

20.有效地括号

class Solution {
    public boolean isValid(String s) {
    Stack<Character> stack = new Stack<>();
    for (char c : s.toCharArray()) {
        if (c == ‘(‘ || c == ‘{‘ || c == ‘[‘) {
            stack.push(c);
        } else {
            if (stack.isEmpty()) {
                return false;
            }
            char cStack = stack.pop();
            boolean b1 = c == ‘)‘ && cStack != ‘(‘;
            boolean b2 = c == ‘]‘ && cStack != ‘[‘;
            boolean b3 = c == ‘}‘ && cStack != ‘{‘;
            if (b1 || b2 || b3) {
                return false;
            }
        }
    }
    return stack.isEmpty();
    }

}

739.每日温度

求数组中元素与下一个比它大元素之间的距离

class Solution {
    public int[] dailyTemperatures(int[] temperatures) {
    int n = temperatures.length;
    int[] dist = new int[n];
    Stack<Integer> indexs = new Stack<>();
    for (int curIndex = 0; curIndex < n; curIndex++) {
        while (!indexs.isEmpty() && temperatures[curIndex] > temperatures[indexs.peek()]) {
            int preIndex = indexs.pop();
            dist[preIndex] = curIndex - preIndex;
        }
        indexs.add(curIndex);
    }
    return dist;
    }
}

503.下一个更大的元素II

class Solution {
   public int[] nextGreaterElements(int[] nums) {
    int n = nums.length;
    int[] next = new int[n];
    Arrays.fill(next, -1);
    Stack<Integer> pre = new Stack<>();
    for (int i = 0; i < n * 2; i++) {
        int num = nums[i % n];
        while (!pre.isEmpty() && nums[pre.peek()] < num) {
            next[pre.pop()] = num;
        }
        if (i < n){
            pre.push(i);
        }
    }
    return next;
    }
}