Sql Server数据批量更新

Posted 2020-09-03 小小高

UPDATE S SET S.[name]=T.[name],S.[sch_id]=T.[sch_id],S.[sex]=T.[sex],S.[isOk]=T.[isOk] FROM [Student] S INNER JOIN 
            (
              SELECT 
‘1010‘ AS id,‘小妹1130946325‘ AS name,‘2‘ AS sch_id,‘gril‘ AS sex,0 AS isOk UNION ALL 
SELECT 
‘1011‘ AS id,‘小子1130946325‘ AS name,‘3‘ AS sch_id,‘boy‘ AS sex,1 AS isOk

            ) T  ON T.[id]=S.[id]