MySql 任务

Posted 2020-08-10

项目7

统计各部门工资最高的员工

create table employee(
 id int not null,
 name varchar(32) not null,
 salary int not null,
 departmentid int not null
 );
insert into employee (id,name,salary,departmentid) values
 (1,‘Joe‘,70000,1),
 (2,‘Henry‘,80000,2),
 (3,‘Sam‘,60000,2),
 (4,‘Max‘,90000,1);
create table department(
 id int not null,
 name varchar(32) not null
 );
insert into department(id,name) values
 (1,‘IT‘),
 (2,‘Sales‘);

select d.name as department, e.name, e.salary from empolyee e
 join (select max(salary) as salary from employee group b departmentid)
 as g on e.salary=g.salary
 left join department d on e.departmentid=d.id;