《漫画算法2》源码整理-2 图算法
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GraphUtil
import java.util.LinkedList;
public class GraphUtil
//深度优先遍历
public static void dfs(Graph graph, int start, boolean[] visited)
System.out.println(graph.vertexes[start].data);
visited[start] = true;
for (int index : graph.adj[start])
if (!visited[index])
dfs(graph, index, visited);
//广度优先遍历
public static void bfs(Graph graph, int start, boolean[] visited, LinkedList<Integer> queue)
queue.offer(start);
while (!queue.isEmpty())
int front = queue.poll();
if (visited[front])
continue;
System.out.println(graph.vertexes[front].data);
visited[front] = true;
for (int index : graph.adj[front])
queue.offer(index);;
//图的顶点
private static class Vertex
int data;
Vertex(int data)
this.data = data;
//图(邻接表形式)
private static class Graph
private int size;
private Vertex[] vertexes;
private LinkedList<Integer>[] adj;
Graph(int size)
this.size = size;
//初始化顶点和邻接矩阵
vertexes = new Vertex[size];
adj = new LinkedList[size];
for (int i = 0; i < size; i++)
vertexes[i] = new Vertex(i);
adj[i] = new LinkedList();
public static void main(String[] args)
Graph graph = new Graph(6);
graph.adj[0].add(1);
graph.adj[0].add(2);
graph.adj[0].add(3);
graph.adj[1].add(0);
graph.adj[1].add(3);
graph.adj[1].add(4);
graph.adj[2].add(0);
graph.adj[3].add(0);
graph.adj[3].add(1);
graph.adj[3].add(4);
graph.adj[3].add(5);
graph.adj[4].add(1);
graph.adj[4].add(3);
graph.adj[4].add(5);
graph.adj[5].add(3);
graph.adj[5].add(4);
System.out.println("图的深度优先遍历:");
dfs(graph, 0, new boolean[graph.size]);
System.out.println("图的广度优先遍历:");
bfs(graph, 0, new boolean[graph.size], new LinkedList<Integer>());
单源最短路径算法 Dijkstra 算法
import java.util.*;
public class Dijkstra
// Dijkstra最短路径算法
public static int[] dijkstra(Graph graph, int startIndex)
//图的顶点数量
int size = graph.vertexes.length;
//创建距离表,存储从起点到每一个顶点的临时距离
int[] distances = new int[size];
//记录顶点遍历状态
boolean[] access = new boolean[size];
//初始化最短路径表,到达每个顶点的路径代价默认为无穷大
for (int i = 1; i < size; i++)
distances[i] = Integer.MAX_VALUE;
//遍历起点,刷新距离表
access[0] = true;
List<Edge> edgesFromStart = graph.adj[startIndex];
for (Edge edge : edgesFromStart)
distances[edge.index] = edge.weight;
//主循环,重复遍历最短距离顶点和刷新距离表的操作
for (int i = 1; i < size; i++)
//寻找最短距离顶点
int minDistanceFromStart = Integer.MAX_VALUE;
int minDistanceIndex = -1;
for (int j = 1; j < size; j++)
if (!access[j] && (distances[j] < minDistanceFromStart))
minDistanceFromStart = distances[j];
minDistanceIndex = j;
if (minDistanceIndex == -1)
break;
//遍历顶点,刷新距离表
access[minDistanceIndex] = true;
for (Edge edge : graph.adj[minDistanceIndex])
if (access[edge.index])
continue;
int weight = edge.weight;
int preDistance = distances[edge.index];
if ((weight != Integer.MAX_VALUE) &&
((minDistanceFromStart + weight) < preDistance))
distances[edge.index] = minDistanceFromStart + weight;
return distances;
// Dijkstra最短路径算法(返回完整路径)
public static int[] dijkstraV2(Graph graph, int startIndex)
//图的顶点数量
int size = graph.vertexes.length;
//创建距离表,存储从起点到每一个顶点的临时距离
int[] distances = new int[size];
//创建前置定点表,存储从起点到每一个顶点的已知最短路径的前置节点
int[] prevs = new int[size];
//记录顶点遍历状态
boolean[] access = new boolean[size];
//初始化最短路径表,到达每个顶点的路径代价默认为无穷大
for (int i = 0; i < size; i++)
distances[i] = Integer.MAX_VALUE;
//遍历起点,刷新距离表
access[0] = true;
List<Edge> edgesFromStart = graph.adj[startIndex];
for (Edge edge : edgesFromStart)
distances[edge.index] = edge.weight;
prevs[edge.index] = 0;
//主循环,重复 遍历最短距离顶点和刷新距离表 的操作
for (int i = 1; i < size; i++)
//寻找最短距离顶点
int minDistanceFromStart = Integer.MAX_VALUE;
int minDistanceIndex = -1;
for (int j = 1; j < size; j++)
if (!access[j] && (distances[j] < minDistanceFromStart))
minDistanceFromStart = distances[j];
minDistanceIndex = j;
if (minDistanceIndex == -1)
break;
//遍历顶点,刷新距离表
access[minDistanceIndex] = true;
for (Edge edge : graph.adj[minDistanceIndex])
if (access[edge.index])
continue;
int weight = edge.weight;
int preDistance = distances[edge.index];
if ((weight != Integer.MAX_VALUE) &&
((minDistanceFromStart + weight) < preDistance))
distances[edge.index] = minDistanceFromStart + weight;
prevs[edge.index] = minDistanceIndex;
return prevs;
private static void printPrevs(Vertex[] vertexes, int[] prev, int i)
if (i > 0)
printPrevs(vertexes, prev, prev[i]);
System.out.println(vertexes[i].data);
private static void initGraph(Graph graph)
graph.vertexes[0] = new Vertex("A");
graph.vertexes[1] = new Vertex("B");
graph.vertexes[2] = new Vertex("C");
graph.vertexes[3] = new Vertex("D");
graph.vertexes[4] = new Vertex("E");
graph.vertexes[5] = new Vertex("F");
graph.vertexes[6] = new Vertex("G");
graph.adj[0].add(new Edge(1, 5));
graph.adj[0].add(new Edge(2, 2));
graph.adj[1].add(new Edge(0, 5));
graph.adj[1].add(new Edge(3, 1));
graph.adj[1].add(new Edge(4, 6));
graph.adj[2].add(new Edge(0, 2));
graph.adj[2].add(new Edge(3, 6));
graph.adj[2].add(new Edge(5, 8));
graph.adj[3].add(new Edge(1, 1));
graph.adj[3].add(new Edge(2, 6));
graph.adj[3].add(new Edge(4, 1));
graph.adj[3].add(new Edge(5, 2));
graph.adj[4].add(new Edge(1, 6));
graph.adj[4].add(new Edge(3, 1));
graph.adj[4].add(new Edge(6, 7));
graph.adj[5].add(new Edge(2, 8));
graph.adj[5].add(new Edge(3, 2));
graph.adj[5].add(new Edge(6, 3));
graph.adj[6].add(new Edge(4, 7));
graph.adj[6].add(new Edge(5, 3));
//图的顶点
private static class Vertex
String data;
Vertex(String data)
this.data = data;
//图的边
private static class Edge
int index;
int weight;
Edge(int index, int weight)
this.index = index;
this.weight = weight;
// 图
private static class Graph
private Vertex[] vertexes;
private LinkedList<Edge>[] adj;
Graph(int size)
//初始化顶点和邻接矩阵
vertexes = new Vertex[size];
adj = new LinkedList[size];
for (int i = 0; i < adj.length; i++)
adj[i] = new LinkedList<Edge>();
public static void main(String[] args)
Graph graph = new Graph(7);
initGraph(graph);
int[] distances = dijkstra(graph, 0);
System.out.println(distances[6]);
System.out.println("输出完整路径:");
int[] prevs = dijkstraV2(graph, 0);
printPrevs(graph.vertexes, prevs, graph.vertexes.length- 1);
多源最短路径算法 Floyd 算法
public class Floyd
final static int INF = Integer.MAX_VALUE;
public static void floyd(int[][] matrix)
//循环更新矩阵的值
for (int k = 0; k < matrix.length; k++)
for (int i = 0; i < matrix.length; i++)
for (int j = 0; j < matrix.length; j++)
if ((matrix[i][k] == INF) || (matrix[k][j] == INF))
continue;
matrix[i][j] = Math.min(matrix[i][j], matrix[i][k] + matrix[k][j]);
// 打印floyd最短路径的结果
System.out.printf("最短路径矩阵: \\n");
for (int i = 0; i < matrix.length; i++)
for (int j = 0; j < matrix.length; j++)
System.out.printf("%3d ", matrix[i][j]);
System.out.printf("\\n");
public static void main(String[] args)
int[][] matrix =
0, 5, 2, INF, INF, INF, INF ,
5, 0, INF, 1, 6, INF, INF ,
2, INF, 0, 6, INF, 8, INF ,
INF, 1, 6, 0, 1, 2, INF ,
INF, 6, INF, 1, 0, INF, 7 ,
INF, INF, 8, 2, INF, 0, 3 ,
INF, INF, INF, INF, 7, 3, 0
;
floyd(matrix);
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