如何在烧瓶SQL炼金术中使用分组依据

Question

我有两个桌子

class MinMaxDim(db.Model):
   min_max_id = db.Column(db.Integer, primary_key=True)
   user_id = db.Column(db.Integer, nullable=False)
   room_id = db.Column(db.Integer, nullable=True)
   min_temp = db.Column(db.Integer, nullable=True)
   max_temp = db.Column(db.Integer, nullable=True)
   min_humidity = db.Column(db.Integer, nullable=True)
   max_humidity = db.Column(db.Integer, nullable=True)
   min_pressure = db.Column(db.Integer, nullable=True)
   max_pressure = db.Column(db.Integer, nullable=True)


class AvgDim(db.Model):
  avg_id = db.Column(db.Integer, primary_key=True)
  user_id = db.Column(db.Integer, nullable=False)
  room_id = db.Column(db.Integer, nullable=True)
  avg_temp = db.Column(db.Integer, nullable=True)
  avg_humidity = db.Column(db.Integer, nullable=True)
  avg_pressure = db.Column(db.Integer, nullable=True)

需求：

我将把room_id作为参数发送给函数，它应该返回两个表中最近7天的min_temp，max_temp和avg_temp值。

我尝试过的：

我创建了一个函数，因为我已经使用了group_by函数，但出现此错误：

  (psycopg2.errors.GroupingError) column "min_max_dim.min_max_id" must appear in the GROUP BY clause 
   or be used in an aggregate function

我的代码：

     def get_weekly_dim_dataInfo(room_id):
        try:
           get_all_data = db.session.query(MinMaxDim).outerjoin(AvgDim, MinMaxDim.user_id ==
                           MinMaxDim.tenant_id).group_by(MinMaxDim.room_id).all()
           get_all_data_schema = MinMaxDimSchema(many=True).dump(get_all_data)
           get_all_avg_data_schema = AvgDimSchema(many=True).dump(get_all_data)
           print(get_all_data)
         except Exception as e:
             print(e)
             return False