如何在MYSQL中获取日期的MIN和MAX（）

Posted 2021-04-28

我有这样的示例数据：

ID Val   Name        o_Dt                 o_gate      c_Dt             c_gate
1, 145, 'Test1', '2020-01-28 02:18:00', 'open'        NULL               NULL
2, 145, 'Test1', '2020-01-28 02:22:00', 'open'        NULL               NULL
3, 145, 'Test1', '2020-01-28 02:26:00', 'open'        NULL               NULL
4, 145, 'Test1', '2020-01-28 04:10:00', 'open'        NULL               NULL
5, 145, 'Test1', '2020-01-28 05:50:00', 'open'  '2020-01-28 05:56:00', 'close'
6, 145, 'Test2', '2020-01-28 07:36:00', 'open'  '2020-01-28 07:45:00'  'close'
7, 145, 'Test2', '2020-01-28 07:42:00', 'open'        NULL               NULL
8, 145, 'Test2', '2020-01-28 07:44:00', 'open'  '2020-01-28 07:47:00', 'close'

如何获得这样的输出：

ID Val   Name        o_Dt                 o_gate      c_Dt             c_gate
1, 145, 'Test1', '2020-01-28 02:18:00', 'open'   '2020-01-28 05:56:00' 'close'
6, 145, 'Test2', '2020-01-28 07:36:00', 'open'  '2020-01-28 07:45:00'  'close'
7, 145, 'Test2', '2020-01-28 07:42:00', 'open'  '2020-01-28 07:47:00', 'close'

我尝试过

MIN(o_Dt)OVER(PARTITION BY c_Dt )

但是它没有给出准确的结果。请建议我

答案

您可以使用一些最小和最大函数

select  min(id) ID, val, Name, min(o_Dt) o_Dt
      , min(o_gate) o_gate, max(c_Dt) c_Dt, max(c_gate) c_gate
from my_table 
group by vat, name