如何在不进行分组的情况下在Oracle中向SQL结果添加虚拟行

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这是我的问题，我正在处理一个现有的大型报告，他们希望我每次数据库中的行满足条件时都添加具有特定值的虚拟行（假设状态=已取消）我将查询（SQL代码的1000行）简化为：：>

如果我有两个表A和B：

Table A
Name            Status              Estimated       Real  
COMPANY A       Completed           $50.00          $50.00   
COMPANY B       Canceled            $0.00           $0.00  
COMPANY C       Not Approved        $100.00     $0.00  
COMPANY D       Withdrawn           $20.00          $10.00   
COMPANY E       Not Approved        $0.00           $0.00  
COMPANY F       Canceled            $1,000.00       $1,000.00
---------------------------------------------------------------

Table B
Name            Status              Estimated       Real  
COMPANY G       In Progress         $50.00          $20.00   
COMPANY H       Not Started         $20.00          $0.00  
COMPANY H       Passed              $100.00     $100.00  
COMPANY I       Approved            $20.00          $00.00   
COMPANY J       Canceled            $14.00          $6.00  
COMPANY A       Scheduled           $2,000.00       $2,000.00

查询就是这样：
SELECT * from (
SELECT NAME,STATUS,ESTIMATED,REAL from A
UNION ALL
SELECT NAME,STATUS,ESTIMATED,REAL from B
) order by name

结果是这样的：
Name            Status              Estimated       Real  
COMPANY A       Completed           $50.00          $50.00   
COMPANY A       Scheduled           $2,000.00       $2,000.00
COMPANY B       Canceled            $0.00           $0.00  
COMPANY C       Not Approved        $100.00     $0.00  
COMPANY D       Withdrawn           $20.00          $10.00   
COMPANY E       Not Approved        $0.00           $0.00  
COMPANY F       Canceled            $1,000.00       $1,000.00
COMPANY G       In Progress         $50.00          $20.00   
COMPANY H       Not Started         $20.00          $0.00  
COMPANY H       Passed              $100.00     $100.00  
COMPANY I       Approved            $20.00          $00.00   
COMPANY J       Canceled            $14.00          $6.00  

现在，我需要做的就是在状态取消时插入虚构的行，如下所示：对于状态=已取消的每一行，添加具有相同名称和估计列的行，状态已计划且实数=0。结果应类似于：（我在虚构行之前添加了**）
Name            Status              Estimated       Real  
COMPANY A       Completed           $50.00          $50.00   
COMPANY A       Scheduled           $2,000.00       $2,000.00
COMPANY B       Canceled            $0.00           $0.00  
**COMPANY B     Scheduled           $0.00           $0.00**  
COMPANY C       Not Approved        $100.00     $0.00  
COMPANY D       Withdrawn           $20.00          $10.00   
COMPANY E       Not Approved        $0.00           $0.00  
COMPANY F       Canceled            $1,000.00       $1,000.00
**COMPANY F     Scheduled           $1,000.00       $0.00**
COMPANY G       In Progress         $50.00          $20.00   
COMPANY H       Not Started         $20.00          $0.00  
COMPANY H       Passed              $100.00     $100.00  
COMPANY I       Approved            $20.00          $00.00   
COMPANY J       Canceled            $14.00          $6.00  
**COMPANY J     Scheduled           $14.00          $0.00**

我尝试使用偶数进行联接或UNION，但是我不知道缺少什么。非常感谢]]

这是我的问题，我正在处理一个现有的大报告，他们希望我每次数据库中的行满足条件时就添加具有特定值的虚拟行（假设状态=已取消）... ...>

在with子查询中简单使用您的查询

with tab as (
SELECT * from (
SELECT "Name","Status" ,"Estimated","Real" from A
UNION ALL
SELECT "Name","Status" ,"Estimated","Real" from B
)
)
select * from tab

并从同一源添加新的UNION ALL查询，仅过滤cancelled行并根据需要管理列：
with tab as (
SELECT * from (
SELECT "Name","Status" ,"Estimated","Real" from A
UNION ALL
SELECT "Name","Status" ,"Estimated","Real" from B
)
)
select * from tab
union all
select "Name", 'Scheduled', "Estimated", 0 "Real"
from tab where "Status" = 'Canceled';

请注意，real不是列名的最佳选择，因为它是保留字
，所以我必须将其用双引号引起来。
  • 示例数据从第1行到第13行
  • 工会（您已经有）是tabunion CTE（第14-18行）
  • 获取应该变成“预定的”已取消的名称（第20-24行）
  • 最终结果是另一个联合
    • SQL> with
  2  taba (name, status, estimated, real) as
  3    (select 'A', 'completed'   ,   50,   50 from dual union all
  4     select 'B', 'canceled'    ,    0,    0 from dual union all
  5     select 'C', 'not approved',  100,    0 from dual union all
  6     select 'F', 'canceled'    , 1000, 1000 from dual
  7    ),
  8  tabb (name, status, estimated, real) as
  9    (select 'G', 'in progress',   50,   20 from dual union all
 10     select 'I', 'approved'   ,   20,    0 from dual union all
 11     select 'J', 'canceled'   ,   14,    6 from dual union all
 12     select 'A', 'scheduled'  , 2000, 2000 from dual
 13    ),
 14  tabunion as
 15    (select name, status, estimated, real from taba
 16     union all
 17     select name, status, estimated, real from tabb
 18    ),
 19  -- canceled statuses that should become "scheduled"
 20  canc as
 21    (select name, 'scheduled' status, estimated, 0 real
 22     from tabunion
 23     where status = 'canceled'
 24    )
 25  -- for final result, union A, B and CANC
 26  select name, status, estimated, real
 27    from tabunion
 28  union all
 29  select name, status, estimated, real
 30    from canc
 31  order by name;

N STATUS        ESTIMATED       REAL
- ------------ ---------- ----------
A completed            50         50
A scheduled          2000       2000
B canceled              0          0
B scheduled             0          0
C not approved        100          0
F canceled           1000       1000
F scheduled          1000          0
G in progress          50         20
I approved             20          0
J scheduled            14          0
J canceled             14          6

11 rows selected.

SQL>
 
    您可以尝试一下，请注意，C是一个内联视图，用于选择虚构的行并与您现有的结果集进行并集。
    SELECT * 
FROM   (SELECT C.name, 
               'Scheduled' AS status, 
               0           AS estimated, 
               0           AS real 
        FROM   (SELECT name, 
                       status 
                FROM   a 
                UNION ALL 
                SELECT name, 
                       status 
                FROM   b) C 
        WHERE  C.status = 'Canceled') 
UNION ALL 
(SELECT name, 
        status, 
        estimated, 
        real 
 FROM   a 
 UNION ALL 
 SELECT name, 
        status, 
        estimated, 
        real 
 FROM   b) 
ORDER  BY name, 
          estimated DESC;
    答案

    在with子查询中简单使用您的查询

    另一答案
    • 示例数据从第1行到第13行
    • 工会（您已经有）是tabunion CTE（第14-18行）
    另一答案

    您可以尝试一下，请注意，C是一个内联视图，用于选择虚构的行并与您现有的结果集进行并集。

    SELECT * 
FROM   (SELECT C.name, 
               'Scheduled' AS status, 
               0           AS estimated, 
               0           AS real 
        FROM   (SELECT name, 
                       status 
                FROM   a 
                UNION ALL 
                SELECT name, 
                       status 
                FROM   b) C 
        WHERE  C.status = 'Canceled') 
UNION ALL 
(SELECT name, 
        status, 
        estimated, 
        real 
 FROM   a 
 UNION ALL 
 SELECT name, 
        status, 
        estimated, 
        real 
 FROM   b) 
ORDER  BY name, 
          estimated DESC;

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