SQLite无法在频繁的“SELECT”查询中打开数据库文件（代码14）

Posted 2021-04-08

我有以下类“Singleton”来处理SQLite连接并确保整个进程/ app有1个连接实例：

public class DBController {
  private static DBController instance = new DBController();
  private static DBHelper dbHelper;
  public static DBController getInstance()
  {
    return instance;
  }
  public SQLiteDatabase dbOpen(Context context)
  {
    if(dbHelper == null)
        dbHelper = new DBHelper(context);
    return dbHelper.getWritableDatabase();
  }
}

而DBHelper类本身：

public class DBHelper extends SQLiteOpenHelper {

  public DBHelper(Context context) {
    super(context, "database.db", null, 1);
  }
  @Override
  public void onCreate(SQLiteDatabase db) {
    final String position = "CREATE TABLE test (" +
            "test TEXT NOT NULL);";
    db.execSQL(position);
  }
}

当我经常尝试从数据库“选择”一些信息时，我收到以下错误：

SQLiteLog: (14) cannot open file at line 31278 of [2ef4f3a5b1]
SQLiteLog: (14) os_unix.c:31278: (24) open(/data/user/0/uz.mycompany.myapp/databases/database.db-journal) - 
SQLiteLog: (14) cannot open file at line 31278 of [2ef4f3a5b1]
SQLiteLog: (14) os_unix.c:31278: (24) open(/data/user/0/uz.mycompany.myapp/databases/database.db-journal) - 
SQLiteLog: (14) statement aborts at 29: [SELECT * FROM test WHERE test='testdata1'] unable to open database file
SQLiteQuery: exception: unable to open database file (code 14); query: SELECT * FROM test WHERE test='testdata1'
android.database.sqlite.SQLiteCantOpenDatabaseException: unable to open database file (code 14)

我正在运行以下代码来执行查询：

public String getData(Context context)
{
    SQLiteDatabase _db = dbOpen(context);
    Cursor c = _db.rawQuery("SELECT * FROM test WHERE test='testdata1'", null);
    return getDataFromCursor(c).get(0); //gets data from cursor and returns first one
}

如何管理/改进我的数据库连接以克服/避免此问题？