MS SQL如何根据最早的日期查询金额

Posted 2021-04-02

我正在加入两个表，tblAccount和tblInvoice。 TblAccount有多个与每个帐户相关的发票。我正在尝试根据最早的InvoiceDate查询TotalSavings金额，如果同一日期有两个金额值，那么我需要将这两个金额相加。我以为我这样做是正确的，但下面的代码并没有给我所需的输出。

SELECT TA.AccountID,
MIN(TI.InvoiceDate) AS InvoiceDate,
TI.TotalSavings
FROM tblAccount AS TA
LEFT JOIN tblInvoice AS TI
ON TA.AccountID=TI.AccountID
WHERE TI.TotalSavings>0
AND
TI.InvoiceDate IS NOT NULL
GROUP BY TA.AccountID, TI.TotalSavings
ORDER BY TA.AccountID

当我加入两个表时，我得到以下结果。

AccountID   Invoice Date    TotalSavings
ABC 6/30/2012   10
ABC 12/31/2013  20
ABC 6/1/2014    30
BCA 9/30/2011   40
BCA 1/31/2012   50
BCA 11/30/2011  60
CBA 3/1/2015    70
CBA 3/1/2015    80

我正在寻找这样的输出

AccountID   Invoice Date    TotalSavings
ABC 6/30/2012   10
BCA 9/30/2011   40
CBA 3/1/2015    150

非常感谢能在这个论坛上提供的任何帮助。

答案

使用joins和subquery

select a.accountid, s.invoicedate, 
       sum(s.TotalSavings) as TotalSavings
from tblAccount a 
left join tblInvoice s on s.accountid = a.accountid 
where s.invoicedate is not null and s.TotalSavings > 0 and
      s.invoicedate = (select min(invoicedate) 
                       from tblInvoice 
                       where accountid = a.accountid)
group by a.accountid, s.invoicedate;

你也可以用joins切换你的exists

select accountid, invoicedate, sum(TotalSavings) as TotalSavings
from tblInvoice s 
where exists (select 1 from tblAccount where accountid  = s.accountid) and 
TotalSavings > 0 and
invoicedate = (select min(invoicedate) from tblInvoice where accountid  = s.accountid)
group by accountid, invoicedate

另一答案

我没有通过模仿像你这样的表来测试下面的代码，但它应该是好的：

; WITH CTE AS (
    SELECT TA.AccountID, MIN(TI.InvoiceDate) AS InvoiceDate
    FROM tblAccount AS TA
        LEFT JOIN tblInvoice AS TI ON TA.AccountID = TI.AccountID -- could be INNER JOIN because you're filtering out the NULL rows on the right with TI.InvoiceDate IS NOT NULL in the WHERE clause
    WHERE TI.TotalSavings > 0 AND TI.InvoiceDate IS NOT NULL
)
SELECT c.AccountID, c.InvoiceDate, SUM(i.TotalSavings) AS TotalSavings
FROM CTE c
    INNER JOIN tblInvoice i ON c.AccountID = i.AccountID AND c.InvoiceDate = i.InvoiceDate
GROUP BY c.AccountID, c.InvoiceDate;

差不多，您首先必须找到某个帐户（TotalSavings > 0）有一些节省的最低发票日期，然后您必须总结该帐户当天的所有节省。

另一答案

根据我的理解，我这样做，你可以使用以下CTE方法。

   with
    rownumber(id, dateColumn, amt, rn)
   as(
    select i.id, dateColumn, sum(amt), ROW_NUMBER() OVER(Partition by i.id 
    ORDER BY dateColumn) rn from tblinvoice i join 
    tblAccount a on a.id = i.id
    group by i.id, dateColumn
   )select id, dateColumn, amt from rownumber where rn = 1


--tlbaccount
id
1
2
3

--tlbInvoice  --same id with same date. And same id with diff date.
id  dateColumn  amt
1   2018-04-14  10
1   2018-04-14  20
2   2018-04-14  20
2   2018-03-14  20

--actual O/P --sum amts of same ids with same date and min date from same id with diff date
id  dateColumn  amt
1   2018-04-14  30
2   2018-03-14  20

另一答案

您不需要null或left。 在哪里杀死左连接的s。 为什么你甚至需要帐户？

select s.accountid, s.invoicedate, 
       sum(s.TotalSavings) as TotalSavings
from tblInvoice s 
where s.TotalSavings > 0 
  and s.invoicedate = ( select min(invoicedate) 
                        from tblInvoice 
                        where accountid = s.accountid )
group by s.accountid
order by s.accountid;