从select语句更新MySQL中的两列

Posted 2021-03-29

我正在尝试更新mysql中的两列：

update table1
set (table1.score, table1.count) = 
(select (table2.maxScore - table2.score ) as diff, count(*)
from table2
where (table2.maxScore - table2.score) <= 600
and table2.age > 50
group by diff);

但是，MySQL不支持这种语法。我已经看过一些使用JOIN的例子，但我不能在这里工作。非常感谢您的帮助！

答案

也许你应该单独设置它们的值，

UPDATE scoresUniverse 
SET scoreUniver.GNfemScore = (Analytics.GN_recency_max_score - Analytics.GN_recency_score ),
ScoresUniverse.GNfemCount = (Select count(*) from Analytics.GN_recency_score where (Analytics.PR_recency_max_score - Analytics.PR_recency_score) <= 600 and Analytics.Older_female_50 > 0)

另一答案

我想到了！ MySQL肯定可以一次更新多个列。我需要更改我的原始查询，因为MySQL在更新多个列时需要使用JOIN和ON。为了证明这一点，我在我的例子中添加了一个额外的列“secondCol”。我已经浏览了整个网络，但从未找到答案。我希望这可以帮助一些人。

 update table1 join
 (select (table2.maxScore - table2.score ) as diff, count(*) as count
 from table2
 where (table2.maxScore - table2.score) <= 600
 and table2.age > 50
 group by diff) as scores
 on table1.count = scores.count
 set table1.score = scores.diff, table1.secondCol = scores.count;