Oracle SQL-将列转换为行，同时保留一列

Posted 2021-03-29

我有下表（它实际上是从复杂逻辑派生的视图）：

|    TYPE | FIELD1 | FIELD2 | FIELD3 | FIELDNEEDSTOSTAYASCOLUMN |
|---------|--------|--------|--------|--------------------------|
|     bad |      1 |      1 |      1 |                     1000 |
| neutral |      2 |      2 |      2 |                     1000 |
|    good |      3 |      3 |      3 |                     1000 |

我需要将其转到下面。占据所有列并将它们移动为thr行，但是我需要保留最后一列。

|   FIELD | BAD    | NEUTRAL| GOOD   | FIELDNEEDSTOSTAYASCOLUMN |
|---------|--------|--------|--------|--------------------------|
| FIELD1  |      1 |      1 |      1 |                     1000 |
| FIELD2  |      2 |      2 |      2 |                     1000 |
| FIELD3  |      3 |      3 |      3 |                     1000 |

我曾尝试使用ORacl的PIVOT和UNPIVOT，但无法创建它。

这是sql的小提琴：

http://sqlfiddle.com/#!4/8fb63/10

答案

select  field, bad, neutral, good, fieldneedstostayascolumn
from    mytable
unpivot (val for (field, ord) in (field1 as ('FIELD1', 1), field2 as ('FIELD2', 2),
                                  field3 as ('FIELD3', 3)))
pivot   (min(val) for type in ('bad' as bad, 'neutral' as neutral, 'good' as good))
order   by ord
;



FIELD   BAD NEUTRAL GOOD FIELDNEEDSTOSTAYASCOLUMN
------ ---- ------- ---- ------------------------
FIELD1    1       2    3                     1000
FIELD2    1       2    3                     1000
FIELD3    1       2    3                     1000

另一答案

您去这里