MS SQL的每日，每周和每月报告
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我想从sql-server表中获取每日，每周和每月报告。
表结构如下：
------------------------------------------
| ItemID | CommentDate |
-----------------------------------------
|989898797 | 2019-04-01 02:51:11.153 |
|----------------------------------------|
|989898797 | 2019-04-01 02:51:11.153 |
|----------------------------------------|
|989898797 | 2019-04-03 02:51:11.153 |
|----------------------------------------|
|989898797 | 2019-04-09 02:51:11.153 |
|----------------------------------------|
|989898797 | 2019-04-11 02:51:11.153 |
|----------------------------------------|
到目前为止，我尝试过以下方法，
select (select count(itemid) from ebayfeedback where ((year(commentdate) = year(getdate()))
and datepart(m,commentdate)=datepart(m,dateadd(month,-1,getdate())))) as lastmonth,
(select count(itemid) from ebayfeedback where (year(commentdate) = year(getdate()))
and datepart(m,commentdate)=datepart(m,dateadd(month,0,getdate()))) as thismonth,
(select count(itemid) from ebayfeedback where (year(commentdate) = year(getdate()))
and datepart(wk,commentdate)=datepart(wk,dateadd(week,1,getdate()))) as lastweek,
(select count(itemid) from ebayfeedback where (year(commentdate) = year(getdate()))
and datepart(wk,commentdate)=datepart(wk,getdate()) group by datepart(wk,commentdate) ) as thisweek,
(select count(itemid) from ebayfeedback where convert(varchar,commentdate,101)=
convert(varchar,dateadd(day,-1,getdate()),101)) as yesterday,
(select count(itemid) from ebayfeedback where convert(varchar,commentdate,101)=
convert(varchar,getdate(),101) ) as today
from ebayfeedback
我从上面的查询中收到多行的结果如下所示。
---------------------------------------------------------
| lastmonth | thismonth | lastweek | thisweek | today |
---------------------------------------------------------
|5 | 5 | 2 | 2 | 1 |
|-------------------------------------------------------|
|5 | 5 | 2 | 2 | 1 |
|-------------------------------------------------------|
|5 | 5 | 2 | 2 | 1 |
|-------------------------------------------------------|
|5 | 5 | 2 | 2 | 1 |
|-------------------------------------------------------|
|5 | 5 | 2 | 2 | 1 |
|-------------------------------------------------------|
我想要每个时期只有一行（1个结果）。请告诉我如何实现这一目标。除了我使用的方法之外，还有什么最好的方法。
期望的结果应该是如下所示的一行。
| lastmonth | thismonth | lastweek | thisweek | today |
---------------------------------------------------------
|5 | 5 | 2 | 2 | 1 |
|-------------------------------------------------------|
注意：我在上面两个表中的示例中给出的数据不是我的实际数据。
答案
解决此问题的一种方法是使用条件聚合查询来基于它创建报告。
首先，创建并填充样本表（请在以后的问题中保存此步骤）：
DECLARE @T AS TABLE
(
ItemID int,
CommentDate datetime
);
INSERT INTO @T (ItemId, CommentDate) VALUES
(989898797, '2019-04-01T02:51:11.153'),
(989898797, '2019-04-01T02:51:11.153'),
(989898797, '2019-04-03T02:51:11.153'),
(989898797, '2019-04-09T02:51:11.153'),
(989898797, '2019-04-11T02:51:11.153');
声明局部变量以使查询更具可读性并防止某些代码重复：
DECLARE @Today date = GETDATE(), -- today's date
@ThisWeek date = DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), GETDATE()), -- first date of the week
@ThisMonth date = DATEADD(DAY, 1 - DATEPART(DAY, GETDATE()), GETDATE()); -- first date of the month
DECLARE @LastMonth date = DATEADD(MONTH, -1, @ThisMonth), -- first date of last month
@LastWeek date = DATEADD(WEEK, -1, @ThisWeek) -- first date of last week
查询：
SELECT COUNT(CASE WHEN CommentDate >= @LastMonth AND CommentDate < @ThisMonth THEN ItemId END) As LastMonth,
COUNT(CASE WHEN CommentDate >= @ThisMonth AND CommentDate < DATEADD(MONTH, 1, @ThisMonth) THEN ItemId END) As thismonth,
COUNT(CASE WHEN CommentDate >= @LastWeek AND CommentDate < @ThisWeek THEN ItemId END) As lastweek,
COUNT(CASE WHEN CommentDate >= @ThisWeek AND CommentDate < DATEADD(WEEK, 1, @ThisWeek) THEN ItemId END) As thisweek,
COUNT(CASE WHEN CommentDate >= @Today AND CommentDate < DATEADD(DAY, 1, @Today) THEN ItemId END) As today
FROM @T
结果：
LastMonth thismonth lastweek thisweek today
0 5 2 0 0
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