mysql——多表——子查询——示例

Posted 2021-03-20 小白龙白龙马

子查询：

子查询是将一个查询语句嵌套在另外一个查询语句中，内层查询语句的查询结果，可以作为外来层查询语句提供查询条件。

因此在特定条件下，一个查询语句的条件，需要另外一个查询语句来获取。

前期准备表：

create table employee ( num int(50),
                        d_id int(50),
                        name varchar(50),
                        age int(50),
                        sex varchar(50),
                        homeadd varchar(50)
                       );



insert into employee values(1,1001,\'zhangsan\',26,\'nan\',\'beijing\');
insert into employee values(2,1001,\'lisi\',24,\'nv\',\'hunan\');
insert into employee values(3,1002,\'wangwu\',25,\'nan\',\'jiangsu\');
insert into employee values(4,1004,\'aric\',15,\'nan\',\'yingguo\');



select * from employee;







create table department ( d_id int(50),
                          d_name varchar(50),
                          functione varchar(50),
                          address varchar(50)
                        );



insert into department values(1001,\'keyanbu\',\'yanfachanpin\',\'3lou5hao\');
insert into department values(1002,\'shengchanbu\',\'shengchanchanp\',\'5louyiceng\');
insert into department values(1003,\'xiaoshoubu\',\'cehuaxiaoshou\',\'1louxiaoshoudating\');




select * from department;

 

一、带in关键字的子查询

select * from employee where d_id in (select d_id from department );

 

 

 

select * from employee where d_id not in (select d_id from department );

 

 

 

 

二、带exists关键字的子查询

exists关键字表示存在，使用exists关键字时，内层查询语句不用返回查询的记录。而是返回一个真假值。

如果内层查询语句查询到满足条件的记录，就返回一个真值（true）；否则，返回一个假值（false）;

当返回值为true时，外层查询语句将进行查询；而返回false时，外层查询语句不进行查询或者查询不出任何记录。

select * from employee where exists (select d_name from department where d_id = 1003);

 

 

 

 

select * from employee where exists (select d_name from department where d_id = 1004);

 

 

 

其它：

exists关键字可以与其他查询条件一起使用。条件表达式与exists关键字之间用and或者or来连接。

select * from employee where age > 24 and exists (select d_name from department where d_id = 1003);

select * from employee where age > 24 and exists (select d_name from department where d_id = 1004);


not exists与exists相反。

select * from employee where age > 24 and not exists (select d_name from department where d_id = 1003);

select * from employee where age > 24 and not exists (select d_name from department where d_id = 1004);

 

 

===================================================================

 

准备语句：

create table schoarship ( levela int(50),
                          score int(50)
                         );


insert into schoarship(levela,score) values(1,90);
insert into schoarship values(2,80);
insert into schoarship values(3,70);


select * from schoarship;




create table computer_stu (  id int(50),
                             name varchar(50),
                             score int(50)
                           );


insert into computer_stu(id,name,score) values (1001,\'lily\',85);

insert into computer_stu(id,name,score) values (1002,\'tom\',91),
                                               (1003,\'jim\',87),
                                               (1004,\'aric\',77),
                                               (1005,\'lucy\',65),
                                               (1006,\'andy\',99),
                                               (1007,\'ada\',85),
                                               (1008,\'jeck\',70);


select * from computer_stu;

 

select * from schoarship;

 

 

select * from computer_stu;

 

 

 

 

3、带比较运算符的子查询

select id,name,score from computer_stu where score >= (select score from schoarship where levela = 1);

/* 查询获得一等奖学金的学生有哪些，第一个表为奖学金等级和最低分数*/

 

 

 

select d_id,d_name from department where d_id != (select d_id from employee where age = 24);

/*只有生产部和销售部没有年龄等于24岁的员工*/

 

 

 

 

 

4、带any关键字的子查询

any关键字表示满足其中任何一个条件。使用any关键字时，只要满足内查询语句返回的结果中的任何一个，就可以通过该条件来执行外层查询语句

 

select * from computer_stu where score >= any ( select score from schoarship );

/*结果显示，有7个人获得奖学金，只有id为1005的人没有，因为分数为65，不高于奖学金指定最低分数的任何一个*/

 

 

 

 

 

 

5、带all关键字的子查询

all关键字表示满足所有条件。使用all关键字时，只有满足内层查询语句返回的所有结果，才可以执行外层查询语句。

 

select * from computer_stu where score >= all ( select score from schoarship );

/*结果显示，只有两个人获得奖学金。因为这两个人的分数比所有奖学金要求的分数都高*/