python利用公式：π/4=1-1/3+1/5-1/7+……，求π的近似值

Posted 2023-02-21

参考技术A #encoding=utf-8

sum = 0
i = 1
t = 1
while abs(t) > 1e-5:
t = (-1)**(i+1)/(2*i-1)
sum += t
i += 1
print('%.5f' % (4*sum))

运行结果
python3 a.py
3.14161 参考技术B precision = 1e-5 #精度
item = 1
i = 1
pi = 0
while item > precision:
item = ((-1)**i) / i

pi_quarter += item
i += 2