MySQL最终任务

Posted thegonedays

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MySQL任务就要完成了

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 任务一

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 sql代码

SELECT 
D.Name Department,
E1.Name Name,
Salary
FROM employee E1
INNER JOIN department D
ON E1.DepartmentId = D.ID
WHERE 
(SELECT COUNT(*)
 FROM employee E2 
WHERE E1.Salary <= E2.Salary AND E1.DepartmentId = E2.DepartmentId)
 <= 3

运行结果:

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 任务二

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sql语句:

SELECT Score,(
SELECT COUNT(*) FROM score
WHERE Score > S.Score)+1 Rank
FROM Score S
ORDER BY Score DESC

 

 查询结果

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任务3

 

 

项目十:行程和用户(难度:困难)
Trips 表中存所有出租车的行程信息。每段行程有唯一键 Id,Client_Id 和 Driver_Id 是 Users 表中 Users_Id 的外键。Status 是枚举类型,枚举成员为 (‘completed’, ‘cancelled_by_driver’, ‘cancelled_by_client’)。
+----+-----------+-----------+---------+--------------------+----------+
| Id | Client_Id | Driver_Id | City_Id |        Status      |Request_at|
+----+-----------+-----------+---------+--------------------+----------+
| 1  |     1     |    10     |    1    |     completed      |2013-10-01|
| 2  |     2     |    11     |    1    | cancelled_by_driver|2013-10-01|
| 3  |     3     |    12     |    6    |     completed      |2013-10-01|
| 4  |     4     |    13     |    6    | cancelled_by_client|2013-10-01|
| 5  |     1     |    10     |    1    |     completed      |2013-10-02|
| 6  |     2     |    11     |    6    |     completed      |2013-10-02|
| 7  |     3     |    12     |    6    |     completed      |2013-10-02|
| 8  |     2     |    12     |    12   |     completed      |2013-10-03|
| 9  |     3     |    10     |    12   |     completed      |2013-10-03| 
| 10 |     4     |    13     |    12   | cancelled_by_driver|2013-10-03|
+----+-----------+-----------+---------+--------------------+----------+
Users 表存所有用户。每个用户有唯一键 Users_Id。Banned 表示这个用户是否被禁止,Role 则是一个表示(‘client’, ‘driver’, ‘partner’)的枚举类型。
+----------+--------+--------+
| Users_Id | Banned |  Role  |
+----------+--------+--------+
|    1     |   No   | client |
|    2     |   Yes  | client |
|    3     |   No   | client |
|    4     |   No   | client |
|    10    |   No   | driver |
|    11    |   No   | driver |
|    12    |   No   | driver |
|    13    |   No   | driver |
+----------+--------+--------+
写一段 SQL 语句查出 2013年10月1日 至 2013年10月3日 期间非禁止用户的取消率。基于上表,你的 SQL 语句应返回如下结果,取消率(Cancellation Rate)保留两位小数。
+------------+-------------------+
|     Day    | Cancellation Rate |
+------------+-------------------+
| 2013-10-01 |       0.33        |
| 2013-10-02 |       0.00        |
| 2013-10-03 |       0.50        |
+------------+-------------------+

 

SELECT Request_at Date_Day,
ROUND(
(
SUM(IF(Status =completed,0,1))
/COUNT(*)
),2)
 Candle_Rate
FROM Trips
WHERE Client_Id IN 
(SELECT Users_Id FROM Users WHERE Banned=No)
OR
 Driver_Id IN 
(SELECT Users_Id FROM Users WHERE Banned=No)
GROUP BY Request_at

 查询结果:

 

 技术图片

 

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