sql语句练习
Posted Luciferl
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了sql语句练习相关的知识,希望对你有一定的参考价值。
-- 1.查询学习课程"python"比课程 "java" 成绩高的学生的学号; -- select python.s_id,student.s_name from ( -- select score.num,score.s_id from course,score where score.c_id = course.c_id and course.c_name = \'python\') as python, -- (select score.num,score.s_id from course,score where score.c_id = course.c_id and course.c_name = \'java\') as java, -- student -- WHERE python.s_id=java.s_id and python.num >java.num and python.s_id =student.s_id -- 查询平均成绩大于65分的同学的姓名和平均成绩(保留两位小数); -- select student.s_name,ROUND(avg(num),2) from student,score where student.s_id =score.s_id GROUP BY student.s_id HAVING avg(num)> 65 -- 查询所有同学的姓名、选课数、总成绩; -- select student.s_name,count(score.c_id) \'课程数\',sum(score.num) \'总成绩\' from student,score WHERE student.s_id =score.s_id GROUP BY score.s_id -- 查询所有的课程的名称以及对应的任课老师姓名; -- select c_name,t_name from course,teacher where course.t_id =teacher.t_id -- 查询没学过“alex”老师课的同学的姓名; -- select student.s_name from (teacher,course,score,student) where ((course.t_id = teacher.t_id) and (score.c_id =course.c_id) and -- (student.s_id=score.s_id)) GROUP BY student.s_id HAVING \'alex\' not in(teacher.t_name)-- 错误 -- select * from score where score.c_id in (select course.c_id from teacher,course where teacher.t_id = course.t_id and t_name = \'alex\') -- select * from student where student.s_id not in(select s_id from score where score.c_id in ((select course.c_id from teacher,course where teacher.t_id = course.t_id and t_name = \'alex\'))) -- 查询学过\'python\'并且也学过编号\'java\'课程的同学的姓名 -- select c_id from course where c_name in(\'python\',\'java\'); -- select * from student where s_id in(select s_id from score where score.c_id in (select c_id from course where c_name in(\'java\',\'python\'))) -- select student.s_name from course,score,student where score.s_id=student.s_id and course.c_id =score.c_id and course.c_name in (\'python\',\'java\') GROUP BY score.s_id HAVING COUNT(*)>=2 -- 查询学过“alex”老师所教的全部课程的同学的姓名 -- SELECT student.s_name from student WHERE student.s_id in (SELECT s_id from score where score.c_id in(SELECT c_id from teacher,course WHERE teacher.t_id =course.t_id and teacher.t_name = \'alex\') GROUP BY score.s_id HAVING count(*)>=2) -- 查询挂科超过两门(包括两门)的学生姓名; -- SELECT s_name from student where student.s_id in(SELECT s_id from score where num <70 GROUP BY score.s_id HAVING count(*)>=2); -- SELECT s_name from student,score where student.s_id =score.s_id and num<70 GROUP BY score.s_id HAVING count(*)>=2; -- 查询有课程成绩小于60分的同学的姓名; -- SELECT s_name FROM student,score where score.num <60 and score.s_id =student.s_id GROUP BY student.s_id; -- SELECT DISTINCT s_name FROM student,score where score.num <60 and score.s_id =student.s_id GROUP BY student.s_id -- 查询选修了全部课程的学生姓名; -- SELECT student.s_name from score,student WHERE score.s_id=student.s_id GROUP BY score.s_id HAVING count(*)=(SELECT count(*) from course)-1 -- 查询至少有一门课程与“貂蝉”同学所学课程相同的同学姓名; -- SELECT DISTINCT s_name from student,score where student.s_id= score.s_id and c_id in (SELECT score.c_id from score,student WHERE score.s_id =(SELECT s_id from student where s_name = \'貂蝉\') and student.s_id= score.s_id) and student.s_name!=\'貂蝉\' -- -- 查询学过\'貂蝉\'同学全部课程 的其他同学姓名; -- SELECT s_name from student,score where student.s_id= score.s_id and c_id in (SELECT score.c_id from score,student WHERE score.s_id =(SELECT s_id from student where s_name = \'貂蝉\') and student.s_id= score.s_id) and student.s_name!=\'貂蝉\' GROUP BY score.s_id HAVING count(*)=(SELECT count(*) from score,student WHERE score.s_id =(SELECT s_id from student where s_name = \'貂蝉\') and student.s_id= score.s_id); -- 查询和\'貂蝉\'同学学习的课程完全相同的,其他同学姓名 -- SELECT score.c_id from score,student WHERE score.s_id =(SELECT s_id from student where s_name = \'貂蝉\') and student.s_id= score.s_id -- SELECT * from score,student WHERE score.s_id=student.s_id and score.s_id in (SELECT s_id FROM score GROUP BY score.s_id HAVING count(*)=(SELECT count(*) FROM score,student WHERE score.s_id = student.s_id and student.s_name=\'貂蝉\' GROUP BY score.s_id )) and score.c_id in (1,2) GROUP BY score.s_id HAVING count(*)=2 and student.s_name!=\'貂蝉\' -- 按平均成绩倒序显示所有学生的“python”、“java”、“linux”三门的课程成绩,按如下形式显示: 学生ID,python,java,linux,课程数,平均分 -- SELECT num as \'python\' from score,course WHERE course.c_id =score.c_id and score.s_id=1 and course.c_name = \'python\'; -- SELECT num from score,course WHERE course.c_id =score.c_id and score.s_id=1 and course.c_name = \'java\'; -- SELECT num from score,course WHERE course.c_id =score.c_id and score.s_id=1 and course.c_name = \'linux\'; -- SELECT -- s.s_id as \'学生ID\', -- count(s.c_id) as \'课程数\', -- avg(s.num) as \'平均分\', -- (SELECT num from score,course WHERE course.c_id =score.c_id and score.s_id=s.s_id and course.c_name = \'python\') as \'python\', -- (SELECT num from score,course WHERE course.c_id =score.c_id and score.s_id=s.s_id and course.c_name = \'linux\') as \'linux\', -- (SELECT num from score,course WHERE course.c_id =score.c_id and score.s_id=s.s_id and course.c_name = \'java\') as \'java\' -- FROM score s GROUP BY s.s_id -- 统计各科各分数段人数.显示格式:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60] -- SELECT course.c_id,course.c_name, -- sum(CASE WHEN num BETWEEN 85 and 100 THEN 1 ELSE 0 end )as \'[85-100]\', -- sum(CASE WHEN num BETWEEN 70 and 85 THEN 1 ELSE 0 end )as \'[70-85]\', -- sum(CASE WHEN num BETWEEN 60 and 70 THEN 1 ELSE 0 end )as \'[60-70]\', -- sum(CASE WHEN num < 60 THEN 1 ELSE 0 end )as \'[<60]\' -- from score,course where score.c_id =course.c_id GROUP BY course.c_id -- 查询每门课程被选修的次数 -- SELECT course.c_name,count(*) as \'选修次数\' from score,course WHERE score.c_id=course.c_id GROUP BY score.c_id -- 查询出只选修了一门课程的学生的学号和姓名 -- select s_name,student.s_id FROM score,student WHERE score.s_id=student.s_id GROUP BY score.s_id HAVING count(*)=1 -- 查询学生表中男生、女生各有多少人 -- SELECT s_sex,count(*) FROM student GROUP BY s_sex; -- 查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列 -- SELECT c_id,avg(num) from score GROUP BY c_id ORDER BY avg(num) asc,c_id DESC -- 查询课程名称为“python”,且分数低于60的学生姓名和分数 -- SELECT student.s_name,score.num from score,course,student WHERE score.c_id=course.c_id and student.s_id =score.s_id and course.c_name=\'python\' and score.num <70
以上是关于sql语句练习的主要内容,如果未能解决你的问题,请参考以下文章