mysql日期时间处理

Posted 2021-01-22 Kris-Q

 

获得当前周的周一到周日

select subdate(curdate(),date_format(curdate(),\'%w\')-1)//获取当前日期在本周的周一
select subdate(curdate(),date_format(curdate(),\'%w\')-7)//获取当前日期在本周的周日

 

数据库字段为int 那样where条件这样写：

FROM_UNIXTIME(a.visit_time, \'%Y-%m-%d\') = subdate(
   curdate(),
   date_format(curdate(), \'%w\') - 7

-- 当天

where to_days(时间字段名) = to_days(now());

-- 本周

SELECT * FROM  表名 WHERE YEARWEEK(date_format(时间字段,\'%Y-%m-%d\')) = YEARWEEK(now());

-- 最近7天

SELECT * FROM  表名  where date_sub(curdate(), INTERVAL 7 DAY) <= date (时间字段);

-- 本月

SELECT * FROM  表名 where date_format(时间字段, \'%Y%m\') = date_format(curdate() , \'%Y%m\');

-- 最近30天

SELECT * FROM  表名 WHERE date_sub(curdate(), INTERVAL 30 DAY) <= date(时间字段);

-- 上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , \'%Y%m\' ) , date_format( 时间字段名, \'%Y%m\' ) ) =1

-- 本季度

SELECT * FROM 表名  WHERE QUARTER(create_date)=QUARTER(now());

查询上季度数据

=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

查询本年数据

 YEAR(create_date)=YEAR(NOW());

查询上年数据

 year(create_date)=year(date_sub(now(),interval 1 year));

查询上周的数据

 YEARWEEK(date_format(submittime,\'%Y-%m-%d\')) = YEARWEEK(now())-1;

查询上个月的数据

 

 date_format(submittime,\'%Y-%m\')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),\'%Y-%m\')

 DATE_FORMAT(pudate,\'%Y%m\') = DATE_FORMAT(CURDATE(),\'%Y%m\') ; 
 WEEKOFYEAR(FROM_UNIXTIME(pudate,\'%y-%m-%d\')) = WEEKOFYEAR(now()) 

MONTH(FROM_UNIXTIME(pudate,\'%y-%m-%d\')) = MONTH(now()) 

 YEAR(FROM_UNIXTIME(pudate,\'%y-%m-%d\')) = YEAR(now()) and MONTH(FROM_UNIXTIME(pudate,\'%y-%m-%d\')) = MONTH(now()) 

between  上月最后一天  and 下月第一天 

 

查询距离当前现在6个月的数据

 submittime between date_sub(now(),interval 6 month) and now();

 转载自：https://www.cnblogs.com/zuochuang/p/7985890.html