MS SQL自定义函数IsPositiveInteger

Posted 2021-01-18 Insus.NET

判断字符串是否为正整数，0开始的的数字不算。

 

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

CREATE FUNCTION [dbo].[svf_IsPositiveInteger] 
(
  @string NVARCHAR(MAX)
) RETURNS BIT  --函数返BIT数据类型，是数字返回1，非数字返回0。
AS
BEGIN
    DECLARE @rtv BIT = 1   
    DECLARE @str NVARCHAR(MAX) = LTRIM(RTRIM(ISNULL(@string,\'\')))  --去除前后空格，如果为NULL转为\'\'

    IF ASCII(SUBSTRING(@str, 1, 1)) = 48 --如果字符串第一位为0
    BEGIN
        SET @rtv = 0 --直接判断为非正整数
    END
    ELSE
    BEGIN
        DECLARE @start INT = 1; 
        DECLARE @end INT = LEN(@str) --获取字符串长度
     
        WHILE (@start <= @end)  --循环字符串每一个字符
        BEGIN
            DECLARE @Numeric VARCHAR(1) = \'\'
    
            SET @Numeric = SUBSTRING(@str, @start, @start + 1) -- 每循环一次从左边获取一位字符
 
            IF ASCII(@Numeric) >= 48 AND ASCII(@Numeric) <= 57 --如果是数字
            BEGIN
                SET @start = @start + 1;
                CONTINUE --继续循环             
            END
            ELSE
            BEGIN
                SET @rtv = 0
                BREAK  --跳出循环
            END
        END
    END
    RETURN @rtv
END

Source Code

 

列举例子说明：

CREATE TABLE [dbo].[uTstTable] ([col1] NVARCHAR(20),[col2] NVARCHAR(20),[col3] NVARCHAR(20),[col4] NVARCHAR(20),[col5] NVARCHAR(20),[col6] NVARCHAR(20),[col7] NVARCHAR(20))
GO

INSERT INTO [dbo].[uTstTable] ([col1],[col2],[col3],[col4],[col5],[col6],[col7]) 
VALUES (\'0.65\',\'000435\',\'SF46DG\',\'3800\',\'$54KQ\',\'-0034\',\'-855.4\')
GO


SELECT [dbo].[svf_IsPositiveInteger] ([col1]) AS [col1],
[dbo].[svf_IsPositiveInteger] ([col2]) AS [col2],
[dbo].[svf_IsPositiveInteger] ([col3]) AS [col3],
[dbo].[svf_IsPositiveInteger] ([col4]) AS [col4],
[dbo].[svf_IsPositiveInteger] ([col5]) AS [col5],
[dbo].[svf_IsPositiveInteger] ([col6]) AS [col6],
[dbo].[svf_IsPositiveInteger] ([col7]) AS [col7]
FROM [dbo].[uTstTable] 
GO

Source Code