c# json解析 如何得到text内容 要具体代码

Posted 2023-05-18

"result" : "ok","tuc" : [ "authors" : [ 13 ],"meaningId" : 2397164096556578585,"phrase" : "text" : "机场","language" : "zho" ,"authors" : [ 3266 ],"meaningId" : 1269040436618011315,"phrase" : "text" : "机场","language" : "zho"]

你肯定已经装了json.NET是吧？

 

 

然后你这个字符串存成info.json文件，读取代码如下：

using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.IO;
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
namespace jsonproject

    class Program
    
        static void Main(string[] args)
        
            using (StreamReader reader = File.OpenText("info.json"))
            
                JObject oText = (JObject)JToken.ReadFrom(new JsonTextReader(reader));
                var contents =
                    from p in oText["tuc"]
                    select (string)p["phrase"]["text"];

                foreach (var item in contents)
                
                    Console.WriteLine(item);
                
                System.Console.ReadKey();
            
        
    

追问

基本成功了，汉字不识别有乱码

追答

文件要存成UTF-8格式。

参考技术A "errorCode":22000,"data":"xcode":"06b9ed05b37158341d07286be822d843","songList":["queryId":"11277008","songId":11277008,"songName":"\u52c7\u6c14","artistId":"1095","artistName":"\u6881\u9759\u8339","albumId":11276429,"albumName":"\u5979\u0026\u5979 [\u597d\u5973\u771f\u7231\u6b4c]","songPicSmall":"http:\/\/b.hiphotos.baidu.com\/ting\/pic\/item\/18d8bc3eb13533fa50437d0daad3fd1f41345b18.jpg","songPicBig":"http:\/\/a.hiphotos.baidu.com\/ting\/pic\/item\/9d82d158ccbf6c814c0bc5cbbe3eb13533fa40d1.jpg","songPicRadio":"http:\/\/c.hiphotos.baidu.com\/ting\/pic\/item\/2cf5e0fe9925bc31e1a8efbb5cdf8db1cb137018.jpg","lrcLink":"\/data2\/lrc\/11301207\/11301207.lrc","version":"","copyType":3,"time":238,"linkCode":22000,"songLink":"http:\/\/file.qianqian.com\/\/data2\/music\/42016392\/42016392.mp3?xcode=06b9ed05b3715834080e0c237f8c5ca50a27df109cddc66b\u0026src=\u0022http%3A%2F%2Fpan.baidu.com%2Fshare%2Flink%3Fshareid%3D459557%26uk%3D2503337755\u0022","showLink":"http:\/\/pan.baidu.com\/share\/link?shareid=459557\u0026uk=2503337755","format":"mp3","rate":128,"size":3824863,"relateStatus":"0","resourceType":"2"]
====解析后图片：

这是WinForm项目，源中的\u52c7\u6c14等要转换为中文。 参考技术B 您先定义一个实体来类
Att_Machine_RecordModel

[Serializable]
public partial class Att_Machine_RecordModel

public Att_Machine_RecordModel()

#region Model

/// <summary>
///
/// </summary>
public int PId=0;

/// <summary>
///
/// </summary>
public string AttCode= "";

/// <summary>
///
/// </summary>
public string CheckTime= "";

/// <summary>
///
/// </summary>
public string CheckType="";

/// <summary>
///
/// </summary>
public string LastModifyTime="";

/// <summary>
///
/// </summary>
public int MachineNum=0;

/// <summary>
///
/// </summary>
public string EntityState="";

/// <summary>
///
/// </summary>
public string EntityKey ="";

#endregion Model


然后把这段文字
string _JsonText = System.IO.File.ReadAllText(@"C:\inetpub\wwwroot\test\2014-08-151.txt");
List<Att_Machine_RecordModel> list = new List<Att_Machine_RecordModel>();
System.Runtime.Serialization.Json.DataContractJsonSerializer _Json = new System.Runtime.Serialization.Json.DataContractJsonSerializer(list.GetType());
byte[] _Using = System.Text.Encoding.UTF8.GetBytes(_JsonText);
System.IO.MemoryStream _MemoryStream = new System.IO.MemoryStream(_Using);
_MemoryStream.Position = 0;
list = (List<Att_Machine_RecordModel>)_Json.ReadObject(_MemoryStream);

foreach(var v in list)

AddAtt_Machine_Record(DefaultDBString, v);
追问

这是什么。。。

追答

我已经写了呀
list = (List)_Json.ReadObject(_MemoryStream);
就是转换成List，然后通过list的对象Att_Machine_RecordModel取值呀

追问

AddAtt_Machine_Record(DefaultDBString, v);出错了

追答

靠， list = (List)_Json.ReadObject(_MemoryStream);
就是您要的结果呀

参考技术C 准备数据
实体类：
[DataContract]
public class Person

[DataMember(Order = 0, IsRequired = true)]
public string Name get; set;

[DataMember(Order = 1)]
public int Age get; set;

[DataMember(Order = 2)]
public bool Alive get; set;

[DataMember(Order = 3)]
public string[] FavoriteFilms get; set;

[DataMember(Order = 4)]
public Person Child get; set;


定义：
Action<object> log = o => Console.WriteLine(o);
Func<int, int, int> add = (x, y) => x + y;

var p1 = new Person
Age = 12,
Alive = true,
Name = "lj",
FavoriteFilms = new[] "Up", "Avatar"
;
var p2 = new Person() Age = 28, Name = "cy", Child = p1 ; 参考技术D "result" : "ok","tuc" : [ "authors" : [ 13 ],"meaningId" : 2397164096556578585,"phrase" : "text" : "机场","language" : "zho" ,"authors" : [ 3266 ],"meaningId" : 1269040436618011315,"phrase" : "text" : "机场","language" : "zho"]

如何使用 C# 将 JSON 对象解析为类

【中文标题】如何使用 C# 将 JSON 对象解析为类

【英文标题】：How to parse a JSON object into class using C#

【发布时间】：2021-07-03 03:02:24

【问题描述】：

我的 Json 对象

"returnStatus":"code":"0200","status":"SUCCESS","message":"The operation was successful.","requestTime":"20210407141112083","responseTime":"20210407141112256","allCities":["cityID":2622,"cityName":" UNKNOWN","cityCode":"AAA","area":"KHI"

我想解析成class.How？ 如何获取cityID、CityName、cityCode、area等。

我正在尝试这段代码

allCities Cities = JsonConvert.DeserializeObject<dynamic>(response);

【问题讨论】：

好的，然后？您发布的代码有什么问题？

我们得到这种类型的错误。解析值时遇到意外字符

您发布的 json 无效（缺少 "]" 这些关闭标签）。

不要使用dynamic，除非你真的，真的必须这样做。只需创建一个代表 JSON 的类，就像 Ryan Thoma 的回答所建议的那样。

【参考方案1】：

您可以像 Ryan 之前所说的那样使用在线工具从您的 json 创建类。但我更喜欢使用 Visual Studio 中集成的“Paste Special”功能。

【参考方案2】：

您可以使用Json2CSharp 创建类来反序列化您的对象。如果您愿意，可以相应地重命名它们。

// Root myDeserializedClass = JsonConvert.DeserializeObject<Root>(myJsonResponse); 
public class ReturnStatus

    public string code  get; set; 
    public string status  get; set; 
    public string message  get; set; 
    public string requestTime  get; set; 
    public string responseTime  get; set; 


public class AllCity

    public int cityID  get; set; 
    public string cityName  get; set; 
    public string cityCode  get; set; 
    public string area  get; set; 


public class Root

    public ReturnStatus returnStatus  get; set; 
    public List<AllCity> allCities  get; set; 

然后您可以使用 myDeserializedClass.allCities 访问城市列表。