MYSQL命令行输入密码警告问题"mysql: [Warning]"解决
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1.1 问题显示
[[email protected] ~]# mysql -uroot -p1234567
mysql: [Warning] Using a password on the command line interface can be insecure.
1.2 解决方法
1.2.1 方法一
1、将密码写入到主配置文件中
[[email protected] ~]# vim /etc/my.cnf
[mysqldump]
user=root
password=1234567
[mysql]
user=root
password=1234567
2、直接使用命令登录,再也无需输入账号密码
[[email protected] ~]# mysql
Welcome to the MySQL monitor. Commands end with ; or g.
Your MySQL connection id is 10
Server version: 5.7.18-log Source distribution
Copyright (c) 2000, 2017, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type ‘help;‘ or ‘h‘ for help. Type ‘c‘ to clear the current input statement.
mysql>
1.2.2 方法二
1、自动配置MYSQL密文密码
该操作会在用户家目录下生成一个隐藏文件".mylogin.cnf",里面记录了MYSQL的密文的密码,只要配置了以后,我们也是直接使用命令登录,再也无需输入账号密码了,如果你想取消,删除此文件即可。
[[email protected] ~]# mysql_config_editor set --user=root --host=localhost --port=3306 --password
Enter password: 输入密码
2、直接使用命令登录,再也无需输入账号密码
[[email protected] ~]# mysql
Welcome to the MySQL monitor. Commands end with ; or g.
Your MySQL connection id is 11
Server version: 5.7.18-log Source distribution
Copyright (c) 2000, 2017, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type ‘help;‘ or ‘h‘ for help. Type ‘c‘ to clear the current input statement.
mysql>
1.2.3 方法三
1、直接使用命令登录,屏蔽错误信息
由于告警信息是标准错误,我们可以将标准错误的输出信息输出为空。
[[email protected] ~]# mysql -uroot -p1234567 2>/dev/null
Welcome to the MySQL monitor. Commands end with ; or g.
Your MySQL connection id is 36
Server version: 5.7.18-log Source distribution
Copyright (c) 2000, 2017, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type ‘help;‘ or ‘h‘ for help. Type ‘c‘ to clear the current input statement.
mysql>
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