使用python实现将秒转化为天时分

Posted 2023-02-19 枫奇

在计算时间差的时候，比较容易得到timedelta这样的格式

比如：

>>> import datetime
>>> datetime.datetime.now()-datetime.datetime(2021,1,1)
datetime.timedelta(days=150, seconds=40790, microseconds=833309)
>>> a = datetime.datetime.now()-datetime.datetime(2021,1,1)
>>> a
datetime.timedelta(days=150, seconds=40806, microseconds=749774)
>>> str(a)
'150 days, 11:20:06.749774'
>>> a.days
150
>>> a.seconds
40806
>>> 

这里如果仅仅是输出天数，就很容易得到，但是具体一点的信息显示的不是很友好

因此可以先利用函数将其全部转化为秒，然后再计算

>>> (datetime.datetime.now()-datetime.datetime(2021,1,1)).total_seconds()
13000936.085446

然后利用下面的函数就能转化为具体花费的多少时间

 

def seconds_to_dhms(seconds):
    def _days(day):
        return " days, ".format(day) if day > 1 else " day, ".format(day)
    def _hours(hour):  
        return " hours, ".format(hour) if hour > 1 else " hour, ".format(hour)
    def _minutes(minute):
        return " minutes and ".format(minute) if minute > 1 else " minute and ".format(minute)
    def _seconds(second):  
        return " seconds".format(second) if second > 1 else " second".format(second)          
    days = seconds // (3600 * 24)
    hours = (seconds // 3600) % 24
    minutes = (seconds // 60) % 60
    seconds = seconds % 60
    if days > 0 :
        return _days(days)+_hours(hours)+_minutes(minutes)+_seconds(seconds)
    if hours > 0 :
        return _hours(hours)+_minutes(minutes)+_seconds(seconds)
    if minutes > 0 :
        return _minutes(minutes)+_seconds(seconds)
    return _seconds(seconds)

举个例子：

> seconds_to_dhms(a)
'1 day, 0 hour, 1 minute and 2 seconds'
>>> a = 24*60*60*45 + 60*13+59 
>>> seconds_to_dhms(a)
'45 days, 0 hour, 13 minutes and 59 seconds'
>>> a = 24*60*60*45 + 60*13+59 +60*34
>>> seconds_to_dhms(a)
'45 days, 0 hour, 47 minutes and 59 seconds'
>>> a = 24*60*60*45 + 60*13+59 +60*60*34
>>> seconds_to_dhms(a)
'46 days, 10 hours, 13 minutes and 59 seconds'
>>> a = 24*60*60*45 + 60*13+59 +60*60*14
>>> seconds_to_dhms(a)
'45 days, 14 hours, 13 minutes and 59 seconds'

这样单复数都有了，如果是中文显示，就更简单一点了，直接在最后格式化输出就好了，不用再定义里面的四个小函数了