SQLLINQLambda 三种用法
Posted Rexcnblog
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了SQLLINQLambda 三种用法相关的知识,希望对你有一定的参考价值。
查询Student表中的所有记录的Sname、Ssex和Class列
select sname,ssex,class from student Linq: from s in Students select new { s.SNAME, s.SSEX, s.CLASS } Lambda: Students.Select( s => new { SNAME = s.SNAME,SSEX = s.SSEX,CLASS = s.CLASS })
查询教师所有的单位即不重复的Depart列
select distinct depart from teacher Linq: from t in Teachers.Distinct() select t.DEPART Lambda: Teachers.Distinct().Select( t => t.DEPART)
查询Student表的所有记录
select * from student Linq: from s in Students select s Lambda: Students.Select( s => s)
查询Score表中成绩在60到80之间的所有记录
select * from score where degree between 60 and 80 Linq: from s in Scores where s.DEGREE >= 60 && s.DEGREE < 80 select s Lambda: Scores.Where( s => ( s.DEGREE >= 60 && s.DEGREE < 80 ) )
查询Score表中成绩为85,86或88的记录
select * from score where degree in (85,86,88) Linq: In from s in Scores where ( new decimal[]{85,86,88} ).Contains(s.DEGREE) select s Lambda: Scores.Where( s => new Decimal[] {85,86,88}.Contains(s.DEGREE)) Not in from s in Scores where !( new decimal[]{85,86,88} ).Contains(s.DEGREE) select s Lambda: Scores.Where( s => !(new Decimal[]{85,86,88}.Contains(s.DEGREE))) Any()应用:双表进行Any时,必须是主键为(String) CustomerDemographics CustomerTypeID(String) CustomerCustomerDemos (CustomerID CustomerTypeID) (String) 一个主键与二个主建进行Any(或者是一对一关键进行Any) 不可,以二个主键于与一个主键进行Any from e in CustomerDemographics where !e.CustomerCustomerDemos.Any() select e from c in Categories where !c.Products.Any() select c
查询Student表中"95031"班或性别为"女"的同学记录
select * from student where class =‘95031‘ or ssex= N‘女‘ Linq: from s in Students where s.CLASS == "95031" || s.CLASS == "女" select s Lambda: Students.Where(s => ( s.CLASS == "95031" || s.CLASS == "女"))
以Class降序查询Student表的所有记录
select * from student order by Class DESC Linq: from s in Students orderby s.CLASS descending select s Lambda: Students.OrderByDescending(s => s.CLASS)
以Cno升序、Degree降序查询Score表的所有记录
select * from score order by Cno ASC,Degree DESC Linq:(这里Cno ASC在linq中要写在最外面) from s in Scores orderby s.DEGREE descending orderby s.CNO ascending select s Lambda: Scores.OrderByDescending( s => s.DEGREE) .OrderBy( s => s.CNO)
查询"95031"班的学生人数
select count(*) from student where class = ‘95031‘ Linq: ( from s in Students where s.CLASS == "95031" select s ).Count() Lambda: Students.Where( s => s.CLASS == "95031" ) .Select( s => s) .Count()
查询Score表中的最高分的学生学号和课程号
select distinct s.Sno,c.Cno from student as s,course as c ,score as sc where s.sno=(select sno from score where degree = (select max(degree) from score)) and c.cno = (select cno from score where degree = (select max(degree) from score)) Linq: ( from s in Students from c in Courses from sc in Scores let maxDegree = (from sss in Scores select sss.DEGREE ).Max() let sno = (from ss in Scores where ss.DEGREE == maxDegree select ss.SNO).Single().ToString() let cno = (from ssss in Scores where ssss.DEGREE == maxDegree select ssss.CNO).Single().ToString() where s.SNO == sno && c.CNO == cno select new { s.SNO, c.CNO } ).Distinct()
操作时问题?执行时报错: where s.SNO == sno(这行报出来的) 运算符"=="无法应用于"string"和"System.Linq.IQueryable<string>"类型的操作数 解决: 原:let sno = (from ss in Scores where ss.DEGREE == maxDegree select ss.SNO).ToString() Queryable().Single()返回序列的唯一元素;如果该序列并非恰好包含一个元素,则会引发异常。 解:let sno = (from ss in Scores where ss.DEGREE == maxDegree select ss.SNO).Single().ToString()
查询‘3-105‘号课程的平均分
select avg(degree) from score where cno = ‘3-105‘ Linq: ( from s in Scores where s.CNO == "3-105" select s.DEGREE ).Average() Lambda: Scores.Where( s => s.CNO == "3-105") .Select( s => s.DEGREE) .Average()
查询Score表中至少有5名学生选修的并以3开头的课程的平均分数
select avg(degree) from score where cno like ‘3%‘ group by Cno having count(*)>=5 Linq: from s in Scores where s.CNO.StartsWith("3") group s by s.CNO into cc where cc.Count() >= 5 select cc.Average( c => c.DEGREE) Lambda: Scores.Where( s => s.CNO.StartsWith("3") ) .GroupBy( s => s.CNO ) .Where( cc => ( cc.Count() >= 5) ) .Select( cc => cc.Average( c => c.DEGREE) ) Linq: SqlMethod like也可以这样写: s.CNO.StartsWith("3") or SqlMethods.Like(s.CNO,"%3")
查询最低分大于70,最高分小于90的Sno列
select sno from score group by sno having min(degree) > 70 and max(degree) < 90 Linq: from s in Scores group s by s.SNO into ss where ss.Min(cc => cc.DEGREE) > 70 && ss.Max( cc => cc.DEGREE) < 90 select new { sno = ss.Key } Lambda: Scores.GroupBy (s => s.SNO) .Where (ss => ((ss.Min (cc => cc.DEGREE) > 70) && (ss.Max (cc => cc.DEGREE) < 90))) .Select ( ss => new { sno = ss.Key })
查询所有学生的Sname、Cno和Degree列
select s.sname,sc.cno,sc.degree from student as s,score as sc where s.sno = sc.sno Linq: from s in Students join sc in Scores on s.SNO equals sc.SNO select new { s.SNAME, sc.CNO, sc.DEGREE } Lambda: Students.Join(Scores, s => s.SNO, sc => sc.SNO, (s,sc) => new{ SNAME = s.SNAME, CNO = sc.CNO, DEGREE = sc.DEGREE })
查询所有学生的Sno、Cname和Degree列
select sc.sno,c.cname,sc.degree from course as c,score as sc where c.cno = sc.cno Linq: from c in Courses join sc in Scores on c.CNO equals sc.CNO select new { sc.SNO,c.CNAME,sc.DEGREE } Lambda: Courses.Join ( Scores, c => c.CNO, sc => sc.CNO, (c, sc) => new { SNO = sc.SNO, CNAME = c.CNAME, DEGREE = sc.DEGREE })
查询所有学生的Sname、Cname和Degree列
select s.sname,c.cname,sc.degree from student as s,course as c,score as sc where s.sno = sc.sno and c.cno = sc.cno Linq: from s in Students from c in Courses from sc in Scores where s.SNO == sc.SNO && c.CNO == sc.CNO select new { s.SNAME,c.CNAME,sc.DEGREE }
以上是关于SQLLINQLambda 三种用法的主要内容,如果未能解决你的问题,请参考以下文章